That would depend on what happened to the Earth's radius as well, since gravity depends on the mass of the object and the square of the distance between them. So if the mass were doubled and the radius of the Earth also doubled, the force of gravity would actually go down by half!
The formula for the gravitational force is F = G my me / R2 .
F = your weight
G = gravitational constant
my = your mass
me = earth's mass
R = distance between your center of mass and earth's center of mass
G and my don't change in this discussion, so we'll represent them by 'K'.
Original weight = K me / R2
New weight = K (2me ) / (2R)2
= K (2/4) me / R2 = 1/2 of original weight.
Your weight would decrease by 1/2.
If the mass of the earth suddenly doubled, while its radius and relative density distribution remained constant,
The weight of you and me and every person and object on earth would also double.
Let's take the changes one at a time, so you can see the effect of each one:
-- If the mass of the Earth suddenly doubled, your weight would also double.
-- If the Earth's radius suddenly doubled, so that you were suddenly twice as far away
from its center, your weight would become 1/22 = 1/4 of its original value.
So if both of these impossible things happened at the same time, your weight
would suddenly multiply by (2) x (1/4) = 1/2 of where it started out.
I suppose with "relative mass" you mean, assume the density is the same.
Surface area is proportional to the square of the radius, so the radius would increase by a factor square root of 2, or 20.5 - about 1.414. Volume, and therefore (assuming the same density) mass, is proportional to the cube of the radius, therefore, it will increase by a factor of 2 times the square root of 2, or 21.5 - about 2.818. Now you can use the formula of universal gravitation, with those numbers (mass increases by a factor 2.818, distance increases by a factor 1.414). Clearly, the force (weight) will increase by a factor square root of 2.
The person's distance from the center of the earth would be reduced to 1/2 of its
present distance, so the force of gravity between the earth and the person would
increase by the factor of (2)2 = 4. He would weigh four times his present weight.
Then (assuming Earth's diameter didn't change), weight would also double.
Then (assuming Earth's diameter didn't change), weight would also double.
Then (assuming Earth's diameter didn't change), weight would also double.
Then (assuming Earth's diameter didn't change), weight would also double.
From the Law of Gravity, F=(GmM)/rr where M is the mass of Earth and m the human mass, G=6.67*10^(-11) r is Earth's radius The force F is F=mg also mg=weight where g is the acceleration due to gravity and m the human mass Putting them together, we get that the acceleration due to gravity g, is g=GM/rr From this, we get that if the mass of the Earth was doubled, then the acceleration due to gravity would be doubled. So, F=m2g this means that the human weight would be doubled as well I think the derivation is correct.
Fundamentally, the object's weight would double (2x higher). However, if the Earth's diameter did change, then your distance to it's core which is where the Earth's mass is centered would also change. Gravity is diretly proportional to mass, however it is also inversely dependent upon the square of the distance between the two masses. The distribution of mass within the Earth also has some effect on what you weigh depending on where on Earth you stand, but ignoring this small efect, taking the reverse of the question - if the Earth were the same mass but double the diameter, your weight would be 1/4th of what it is now.
My weight would increase, and so would yours.
Every person's weight is proportional to (the person's mass) times (the earth's mass).
If either mass increases, then so does the person's weight.
Pretty much 92% of the time or more, that happens because the person's mass increases.
But it's certainly technically correct to say that if the earth's mass increased, everyone's
weight would increase just as surely.
the sun's radius is and half a million bigger than the radius of the sun.
Approx 1000 earths would fit into Jupiter
The equatorial circumference is about 40 000 km. This was the original definition of the metre, though better measurements now mean we know the error. [Actually the definition was of 10 000 km for 1/4 of the circumference].
Yes, in a way. If the radius of the Earth decreased but it's mass stayed the same, then the forces "pulling" on you (weight) would increase and you would be heavier. If the radius of the Earth increased and the mass stayed the same, then you would be lighter. You would actually weigh less on the top of Mount Everest than on the beach of Honolulu. BTW: This is not a good idea for a weight loss program.
Jupiter is a gas giant and the largest planet in our solar system. It has an equatorial diameter of 142,800 km (Earth is 12,756 km). Its mass is equivalent to 317 Earths, and its volume equal to 1321 Earths. It has more mass than all of the other solar planets combined. Mass = 1.8986×1027 kg Volume = 1.43128×1015 km³ Radius = 71,492 km's (Earths radius is 6,378 km's) Mass = 317.83 Earths Average density = 1.3g/cm3
Mercury's radius (at the equator) = 2440km or 0.3825 x Earths Venus' radius = 6052km or 0.9488 x Earths Earth's radius = 6378km Mars' radius = 3397km or 0.5323 x Earths Jupiter's radius = 71,492km or 11.21 x Earths Saturn's radius = 60,267km or 9.45 x Earths Uranus' radius = 25,557km or 4.01 x Earths Neptune's radius = 24,766km or 3.88 x Earths
Generally decreased.
Mercurys mean radius is around 2,439.7 km, which is around 38.39% of earth radius or 0.3829 Earths. Mercurys mass is around 3.3022×10 to the 23 kg, around 5.5% of earths mass or 0.055 Earths.
Decreased the FEV1 %
no
resistance is inversily proportional to squaire of radius of wire.
Yes. The area is proportional to the square of the radius. If the radius becomes smaller, so does the area.
the sun's radius is and half a million bigger than the radius of the sun.
Mercury's radius (at the equator) = 2440km or 0.3825 x EarthsVenus' radius = 6052km or 0.9488 x EarthsEarth's radius = 6378kmMars' radius = 3397km or 0.5323 x Earths
In terms of Radius and diameter; Mercury's radius and diameter (at the equator) = 0.3825 x that of Earths (or 38.25%) Venus's radius and diameter = 0.9488 x Earths (nearly 95%) (Earth's radius = 6378km, diameter = 12756km) Mars = 0.5323 x Earths (53.2%) Jupiter = 11.21 x Earths Saturn = 9.45 x Earths Uranus = 4.01 x Earths Neptune = 3.88 x Earths In terms of Volume; Mercury's volume = 0.056 x Earths (or 5.6% of Earths) Venus' volume = 0.857 x Earths (85.7%) (Earths volume = 1.08 x 1012 cubic km (km3)) Mars' volume = 0.151 x Earths (15.1%) Jupiter's volume = 1321.3 x Earths Saturn's volume = 763.59 x Earths Uranus' volume = 63.086 x Earths Neptune's volume = 57.74 x Earths
It reduces by one third.
MarsIts equatorial radius is 3,396.2 ± 0.1 km or 0.533 Earths,Its polar radius is 3,376.2 ± 0.1 km or 0.531 Earths,Its surface area is 144,798,500 km² or 0.284 Earths,Its volume is 1.6318 × 1011 km³ or 0.151 Earths,Its mass is 6.4185 × 1023 kg or 0.107 Earths.