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53
53
There were 52 Sundays and Fridays. There were 53 Saturdays.
It differs from one leap year to another. It will be either 52 or 53. If a leap year starts on a Thursday or a Friday, then it will have 53 Fridays, otherwise it will have 52 Fridays.
53
There were exactly 53 Fridays and 52 Saturdays in the year 2010.
There are 53 Fridays in 2010, the last one of which falls on December 31, 2010.
There are 52 weeks in a year. The answer is 52 Fridays normally, but since the year begins and ends on a Friday, there are 53 Fridays in 2010.
2015 - 1962 = 53 years old on 21st January 2015.
2010 had 52 weeks and 1 day, as normal years do. It started and finished on a Friday, so there were 53 Fridays in it, meaning someone who got paid every Friday, would have had 53 pay days in 2010. You may have meant in relation to that kind of example.
2012 First, 2019 does NOT have 53 Sundays; check out any calendar. Second, ***ONLY 2 YEARS*** in the Twenty-First Century? No. Third try -- By my calculation, in the Twenty-First Century the following 17 years with 53 Sundays: 2006, 2012, 2017, 2023, 2028, 2034, 2040, 2045, 2051, 2056, 2062, 2068, 2073, 2079, 2084, 2090, & 2096. Any year beginning (i.e., 1 Jan) with a Sunday and any leap year beginning with a Saturday (not a Monday, as I earlier indicated) is a year with 53 Sundays. In OpenOffice Calc, that is (Corrected version): =IF(OR(WEEKDAY($B5)=1;AND(INT(YEAR($B5)/4)=YEAR($B5)/4;WEEKDAY($B5)=7));1;0) Correct me if I am wrong.
A leap year is 52 weeks plus 2 days. That means that 2 days have 53 instances. So there is a 2/7 chance that there will be 53 Fridays. There is absolutely no chance that there are 54 Sundays, since 53 is the most you can have. Good luck. The exact probability is 28/97, which is about 28.87%.