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When a 236 kg roller coaster car is released from rest from a height of 40 meters what is the veloity of the car when it gets to a height of 18 meters?
Wiki User
∙ 14y ago
Total Energy is Equal to the Potential Energy plus Kinetic Energy of the rollercoaster car.
Total Energy at 40 m:
PE= (mass)(gravity)(height) = (236kg)(9.81m/s^2)(40m) = 92606.4 J
PE(at 18 meters) = (236kg)(9.81m/s^2)(18m) = 41672.88 J
Total Energy - PE at 18m = Kinetic Energy
KE = (2606.4J)-(41672.88J)= 50933.52 J
KE = (1/2)mv^2 = (.5)(236kg)(v^2)
50933.52 J = (.5)(236kg)(v^2)
V= 20.776 m/s
Wiki User
∙ 14y ago
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