The bullet has a great deal of kinetic energy, because of its high speed. It also has a little
bit of potential energy relative to the ground, because of its height above the ground.
Kinetic, potential, and heat.
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
A cartridge is that cylindrical container that has an explosive inside, a projectile (bullet) on one end, and a cap (like a match) on the other end. It is loaded in the gun. When the trigger of the gun is pulled it causes a firing pin to strike the cap on the cartridge. The cap ignites the explosive in the cartridge causing a very rapid expansion of the combustion gases inside the cartridge. The gases push on the walls of the cartridge and the bullet. The gun supports the walls of the cartridge and prevents the cartridge from deforming or tearing. But something has to give to release all that pressure. The bullet is what gives. The expanding gases push it through the barrel of the gun. If the gun is properly designed the bullet leaves the gun before the friction of the barrel starts to slow it down. If the shooter has aimed the gun properly the bullet hits the target.
The Answer Is: 4 feet per second.
Air resistance and gravity.
A bullet leaves a gun barrel because it is forced out by the pressure of burning gasses.
It is the opening at the front of the gun where the bullet leaves the barrel.
It is the hole at the front end of the barrel where the bullet leaves the gun.
While it is moving, it has kinetic energy. Before it is shot, it has chemical energy - that's what causes the explosion.
yes if your arm is moving at the same speed as the bullet as it leaves the gun
Technically, a 9mm bullet has NO energy, since the bullet is the metal part that leaves the muzzle of the gun when fired. However, the 9mm Parabellum cartridge does have energy. The exact energy varies with the loading of that cartridge- but about 420 ft lbs of energy at the muzzle. Typically this is more than a .38 Special cartridge, less than a .357 Magnum cartridge.
Yes, it is will happen that way. The sound of the blast is caused by the release of gasses at the muzzle of the gun. Those gasses are trapped behind the bullet- pushing it- and are not released until the bullet leaves the gun.
It depends on the type of ammunition.
When you fire most guns, the gun will eject the brass cartridge the holds the bullet, gun powder, and primer. The firing pin of the gun hits the primer at the base of the cartridge, which ignites the gun powder and fires the bullet. As the explosion occurs and the bullet leaves the barrel of gun, the mechanism of the gun uses the explosion's energy to eject the now empty brass cartridge.'Policing the brass' means to pick up the spent cartridges after your done firing.
A bullet reaches it's maximum velocity at the instant it leaves the muzzle of the gun. Once it leaves the gun, it begins to slow- it CANNOT get faster. So the answer to your question is no.
Kinetic, potential, and heat.
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1