Both objects are acted on by the force of the expanding gases in the bore.
The forces forward and backward have to be equal.
The motion they produce ... the forward motion of the shot and the rearward
motion of the cannon ... are in inverse proportion to their masses, so that the
linear momentum after the shot is the same as the linear momentum before the
shot, namely zero.
The forces are equal. Only reasons the ball goes Flying off and the cannon stays in place, is that the cannon is so much heavier than the ball.
Newton's Third Law: the force of the cannon against the cannonball is equal (but opposite in direction) to the force of the cannonball against the cannon.
Because like a cannon when the cannon ball comes out the cannon goes forward that's reaction force. Normal force is where the force does not use a ton of force so you don't see it react.
The forces are equal in both directions. The momentum of the shot is also equal to the momentum of the cannon in the other direction. The backward velocity of the cannon is: (forward velocity of the shot) times (mass of the shot) divided by (mass of the cannon).
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
The same.
30
If fired fast enough, it can either begin orbit (unless/until it hits something else that stops it), or escape Earth's gravity and begin travel through space (again, until it hits something).
Cannon Air Force Base was created in 1943.
The airport code for Cannon Air Force Base is CVS.
Because like a cannon when the cannon ball comes out the cannon goes forward that's reaction force. Normal force is where the force does not use a ton of force so you don't see it react.
The forces are equal in both directions. The momentum of the shot is also equal to the momentum of the cannon in the other direction. The backward velocity of the cannon is: (forward velocity of the shot) times (mass of the shot) divided by (mass of the cannon).
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
The same.
It never existed ....
shadow force hydro cannon dark void Draco meteur
For every reaction there is an equal and opposite reaction. -500N
30
the recoil of a bullet fired from a gun