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When a particle is moving in a circular motion what is the work done by it?
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If displacement of a particle is zero?
If displacement of a particle is zero in a uniform circular motion, then the distance travelled by that particle is not zero, kinetic energy is constant, speed is constant and work done is zero
What is the work done by a body moving along a circular path?
i think it is zero
What is the work done by an electron revolving in a circular orbit of rdius r around the nucleus?
Here a centripetal force provided by electrostatic force of attraction acts on the electron towards the centre of orbit but motion is along the tangent to the circular orbit at ecah point. As force and displacement are in mutually perpendicular directions at each point, the work done is zero. E V SHAKKEER HUSSAIN
Is it possible that a body be in accelarated motion under a force acting on a body yet no work is being done by the force?
Yes, that is possible. For example, an object in circular motion, accelerated towards the center. The force (and the acceleration) is normal (perpendicular) to the movement; thus, the dot product between the force and the displacement is zero.
Why is a ball an example of simple harmonic motion?
because its motion is done repeatedly
If displacement of a particle is zero?
If displacement of a particle is zero in a uniform circular motion, then the distance travelled by that particle is not zero, kinetic energy is constant, speed is constant and work done is zero
What is the work done by a body moving along a circular path?
i think it is zero
When force is to the direction of motion no work is done?
No. Only if you are applying the same amount of force then there is no motion. If you are applying more force (the object is moving) then there is work being done.
What should be the angle between the direction o foce and the direction of motion of a body so that the work done is zero?
Work is zero when the force is perpendicular to the direction of motion, as it is, for example, in a circular gravitational orbit.
What is the past particle for the word do?
done do did done
When body moves in a circular path how much work is done by the body?
Zero. This is because when a body when around in a circle, a centripetal force acts on the particle to keep it at that fixed distance from the centre. At each point, the force and the displacement are perpendicular to each other. Hence no work is done. The answer is NOT Zero! A Force is required in the direction of motion around the circle. At every point (an infinite number of them) there must be a Force PERPENDICULAR to the Centrifugal and Centripetal Forces or the object would not move. Therefore the amount of work done is the product of that FORCE times the circumference of the circular path, if only considering one revolution.
Why light posses dual nature?
light travel as a wave but it carries photon which is consider to be a particle.so photon done function as a particle and wave motion made effect as wave.
What is the past particle of do?
The past participle of do is 'done'.
What is a circular skirt?
A circular skirt is a skirt that is done by cutting just a circle out of a piece of fabric.
What is the work done by an electron revolving in a circular orbit of rdius r around the nucleus?
Here a centripetal force provided by electrostatic force of attraction acts on the electron towards the centre of orbit but motion is along the tangent to the circular orbit at ecah point. As force and displacement are in mutually perpendicular directions at each point, the work done is zero. E V SHAKKEER HUSSAIN
What does Kinetic Energy means?
1/2 x mass x velocity x velocity. The energy possessed by moving object is called the kinetic energy.The kinetic energy of a moving body with certain velocity is equal to the work done on it to make it acquire that velocity.
Is it possible that a body be in accelarated motion under a force acting on a body yet no work is being done by the force?
Yes, that is possible. For example, an object in circular motion, accelerated towards the center. The force (and the acceleration) is normal (perpendicular) to the movement; thus, the dot product between the force and the displacement is zero.
