Formula for distance traveled with constant acceleration is:
S = v0t + at2 / 2.
Knowing the distance, time and that initial velocity is zero:
S = at2 / 2,
a = 2S / t2, or numerically:
a = 804 / 36 = 22.33 m/s2
Expressing that in terms of g(=9.81 m/s2):
a = 2.28 g
The cart's acceleration will be directly proportional to the net force applied to it. If the force remains constant, the acceleration will also remain constant, assuming no other external factors are affecting the cart's motion.
From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.From the formula force = mass x acceleration, if there is more mass, there will be less acceleration. Assuming the force doesn't also change.
Gravity produces acceleration on an object, assuming that no other force acts on the object.
Acceleration is the CHANGE in velocity; you're assuming CONSTANT velocity. So the acceleration is zero.
Near Earth's surface, the acceleration is about 9.8 meters/second2, assuming air resistance can be neglected.
Assuming the mass remains constant, the acceleration will be tripled as well.
72% of the gravitational acceleration - assuming a flat surface.
No, assuming no air resistance, there will be a constant downward acceleration of 9.8 meters per second square (assuming standard gravity). The vertical component of the velocity will be zero at the top of the trajectory.
Yes, assuming the object's rate of acceleration remains positive during the time it is decreasing.
Acceleration is a change in velocity. Assuming a constant direction, if you're speeding up that is positive acceleration. If you are slowing down, that's negative acceleration. Either way you are accelerating.
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
Any change of velocity, including a decrease of speed, is described and measured as acceleration. Assuming the velocity and acceleration vectors point in the same direction, then in the case of decreasing speed, the magnitude of the acceleration is a negative value. Negative acceleration is often called deceleration, but that is just a special case of acceleration.