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Formula for distance traveled with constant acceleration is:

S = v0t + at2 / 2.

Knowing the distance, time and that initial velocity is zero:

S = at2 / 2,

a = 2S / t2, or numerically:

a = 804 / 36 = 22.33 m/s2

Expressing that in terms of g(=9.81 m/s2):

a = 2.28 g

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Q: When a particular race car can cover a quarter mile track 402 m in 6.00 s starting from a standstill Assuming the acceleration is constant how many g's does the driver experience?
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