This depends on whether your resistors are in serial or parallel.
If they are in serial, the value of the resistors just adds up, so :
Val(total) = val(single) x n(umber of resistors)
If they are in parallel, each added resistor lowers the total value, while the power rating rises :
Val(t) = 1/ ( val(s) x n)
5000 For Parallel resistors: Rtotal = R / N Rtotal is total resistance R = Value of resistors N = number of resistors 15 = 75000 / N N = 5000
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
They use a color code. Colored bands on the resistor that tell the value. Some precision resistors have their value written on them.
Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).
If the parallel resistors are equal, then the total resistance (in this case, with three resistors) will decrease by a factor of 3. I suggest you verify this with the standard formula for parallel resistance: 1/R = 1/R1 + 1/R2 + 1/R3, replacing the value 30 for R1, R2, and R3, and calculating R, the combined resistance.
5000 For Parallel resistors: Rtotal = R / N Rtotal is total resistance R = Value of resistors N = number of resistors 15 = 75000 / N N = 5000
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
They use a color code. Colored bands on the resistor that tell the value. Some precision resistors have their value written on them.
It depends on where and how the resistor is placed in a circuit. A string of series resistors will split the voltage across all them depending on their values. All of the resistors in parallel will have the same voltage across all of them no matter what their resistance is.
Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).
Ways to reduce electrical resistance: increase the diameter of the conductor, decrease or increase the temperature of conductor (depending on its thermal characteristics), decrease the length of the conductor. A change in the material out of which the conductor is made can decrease resistance, too. And there is the phenomenon of superconductivity. In a simple circuit the resistance can be lowered by adding resistors in parallel. The total circuit resistance will then decrease. You can also reduce resistance by substituting resistors of lower value, or by adjusting a potentiometer, or pot, to a lower value.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
The resistors each have a value of 20 ohms. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. Your problem gives us an applied voltage of 8 volts and a current flow of 0.2 amps. The formula that probably works best is R = E/I for this one because you have volts and amps. In this case, R = 8/0.2 = 40 ohms. But that's the total resistance in the circuit, and you said that a pair of equal resistors are connected, so the pair of resistors has a total resistance of 40 ohms. The rule for finding total resistance for resistors in series is that we add them up. R1 + R2 = 40 ohms. And since R1 = R2 here, 2 x R1 or 2 = 40 ohms, and R1 or 2 = 20 ohms. Either resistor has a resistance of 20 ohms, and that means they both do. Easy as pie.
There is insufficient information in the question to answer it. 30 volts generating 14 amperes means the two resistors have a total series resistance of 2.143 ohms. Since no relationship was stated, we don't know the value of the individual resistors. If the two resistors had the same resistance, the net parallel resistance would be 0.536 ohms, and a current of 56 amperes would flow.
1.25kFollowing Ohms LawEquation:R = E / I(R=Resistance, E=Voltage, I=Current)Known Values:E = 5vI = 1mA = 0.001AR = 5/0.001R=5000Total Resistance is 5000ohms, since we know there are four equal resistors simply divide by 4R/4=5000/4R=1250ohm=1.25kohm