5000
For Parallel resistors:
Rtotal = R / N
Rtotal is total resistance
R = Value of resistors
N = number of resistors
15 = 75000 / N
N = 5000
The resistors should be connected in parallel .
The smallest resistor.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
When resistors are connected in series, the total resistance is the sum of the individual resistances. When resistors are connected in parallel, the total resistance is less than the smallest individual resistance.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different
Resistors connected in parallel have the same voltage across them, while resistors connected in series have the same current passing through them. In a parallel configuration, the total resistance decreases as more resistors are added, while in a series configuration, the total resistance increases.
The resistors should be connected in parallel .
Resistors in parallel work just like highway lanes in parallel. -- The more lanes there are, the more traffic they can carry. -- Any number of lanes in parallel are always wider than the widest single lane, and can carry more traffic than the widest single lane can. "wide lane" = low resistance "narrow lane" = "high resistance" "traffic" = "electric current"
The smallest resistor.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
It depends on the values of the individual resistors. But if each resistor is identical, then the total resistance will be one-quarter that of an individual resistor.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
To combine resistors in parallel to achieve the desired total resistance, you need to use the formula 1/Rtotal 1/R1 1/R2 1/R3 ... 1/Rn, where Rtotal is the total resistance and R1, R2, R3, etc. are the resistances of the individual resistors. Calculate the total resistance by adding the reciprocals of the individual resistances and then taking the reciprocal of the sum.