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No. V =Voltage, I =current, and R =resistancein the simple equation: V=I*R. As well, V/I=R, and. V/R=Iso Current is voltage divided by resistance
Where V=stands for voltage, I=stands for current and R=stands for resistance. voltage=current multiplied by resistance so, by transposition, resistance=voltage divided by current. or R=V/I, R=9/3 The resistance is 3 ohms.as by ohm's law, v=irr = v/itherefore the resistance is 9/3=3 ohms
Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.
You can not change amp's amps is the result of voltage and resistance. Current is represented by I, Voltage is represented by E and Resistance is represented by R in ohms law. I=E/R, R=E/I and E=IxR the I is never a variable
You can't convert kV (kilovolts) to current (amps) unless you know the resistance (ohms) of the load which is taking current from that voltage source. Once you know the resistance then you can use Ohm's Law to get the amperage: I = V / R In words, Ohm's law is: Current (amps) equals voltage divided by resistance (ohms)
I=V/R The smaller the resistance the greater the amperage.
To answer this question the resistance of the load is needed. I = E/R.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
No. V =Voltage, I =current, and R =resistancein the simple equation: V=I*R. As well, V/I=R, and. V/R=Iso Current is voltage divided by resistance
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
Yes. If one matrix is p*q and another is r*s then they can be multiplied if and only if q = r and, in that case, the result is a p*s matrix.
The resistance is equally proportionate to "r" in the case that it is above 1. Assuming "r" is greater than 1, the resistance is 4/3 multiplied by omega (the equal proportionate value for mass times ohms). If "r" is less than or equal to 1, there is no resistance.
I=v/r =110/121 =0.909A
Ohm's law revisited; Current (amperage) = voltage divided by resistance. E=I/R http://www.glenbrook.k12.il.us/gbssci/Phys/Class/circuits/u9l3c.html http://www.bcae1.com/ohmslaw.htm
Where V=stands for voltage, I=stands for current and R=stands for resistance. voltage=current multiplied by resistance so, by transposition, resistance=voltage divided by current. or R=V/I, R=9/3 The resistance is 3 ohms.as by ohm's law, v=irr = v/itherefore the resistance is 9/3=3 ohms
Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.