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Q: When amperage I is multiplied by resistance R the result is?
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If the resistance changes in a circuit the amperage will also change?

I=V/R The smaller the resistance the greater the amperage.


How do you figure amperage from voltage 1500?

To answer this question the resistance of the load is needed. I = E/R.


What does volts times amperage equal?

Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R


Is current the voltage multiplied by resistance?

No. V =Voltage, I =current, and R =resistancein the simple equation: V=I*R. As well, V/I=R, and. V/R=Iso Current is voltage divided by resistance


Formula for ohms law?

ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms


Voltage across resistor is doubled the current is?

Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.


Can a 3 X 4 matrix be multiplied by a 4 X 1 matrix?

Yes. If one matrix is p*q and another is r*s then they can be multiplied if and only if q = r and, in that case, the result is a p*s matrix.


A cell of emf E volt and its internal resistance is 'r' ohm. The cell is connected to a load of 'R' ohm. The potential difference across the terminals of the cell is?

The resistance is equally proportionate to "r" in the case that it is above 1. Assuming "r" is greater than 1, the resistance is 4/3 multiplied by omega (the equal proportionate value for mass times ohms). If "r" is less than or equal to 1, there is no resistance.


The voltage in the home is 110 volts. a light bulb has a resistance of 121 ohms. what is the amperage passing through the bulb?

I=v/r =110/121 =0.909A


How is Amperage Draw determined in electrical devices?

Ohm's law revisited; Current (amperage) = voltage divided by resistance. E=I/R http://www.glenbrook.k12.il.us/gbssci/Phys/Class/circuits/u9l3c.html http://www.bcae1.com/ohmslaw.htm


How do you calculate the resistance in a circuit in which a 9-volt battery produces 3 amperes?

Where V=stands for voltage, I=stands for current and R=stands for resistance. voltage=current multiplied by resistance so, by transposition, resistance=voltage divided by current. or R=V/I, R=9/3 The resistance is 3 ohms.as by ohm's law, v=irr = v/itherefore the resistance is 9/3=3 ohms


When the resistance in an electrical circuit increases and the voltage does not change the current flowing in the circuit?

Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.