Radioactive decay and ionic bonds (if the bond is broken, the electron goes back).
An atom can lose electrons to other atoms during a chemical reaction. This process results in the atom becoming positively charged, forming an ion.
The contact with an atom having a high affinity for electrons.
The gain and/or lose of electrons.
You question is a bit incorrect. Beryllium is a metallic element in Group (II) of the Periodic Table. Being in Group (II) it will have a strong tendency to loose electrons(ionisation). In its neutral state beryllium has the electron structure of 1s2, 2s2, This means that its inner most electron shell (1s) contains two electrons. Its outer most electron shell (2s) also contains two electrons. When beryllium ionises two electrons , they are 'lost' from the outer most (2s) electron shell. They are further from the nucleus of the atom and are not so strongly held.!!!!! When these two electrons have 'gone' , the Beryllium atom is now the Beryllium ION. (It is no longer an atom). Formulaically it is written as Be(g) = Be^(2+) + 2 e^(-) So for beryllium atom to become a Beryllium ION it LOSES TWO electrons.
lose one or more electrons.
No. A metallic atom will typically lose electrons.
A full outer electron shell. Atoms tend to be more stable when they have a full valence shell, which typically contains eight electrons. This stability makes it less likely for the atom to either lose or gain electrons.
A Fluorine atom has an atomic number of 9. Draw out the electron shell diagram for Fluorine. Is a Fluorine atom more likely to gain, lose or share electrons to fill its valence shell?
Electrons in the outer most shell are called Valence Electrons.
The kind of atom that likes to be oxidized.
No - it would want to lose these two electrons
Lithium loses electrons.