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The amount of energy that is absorbed is the same as the amount of energy that is released.
When an electron returns to its ground state it emits energy in the form of light.
Lots of wrong answers out there, tested this on school, the answer is: Drops from a higher to a lower energy level
In beta- decay, an electron and an electron antineutrino is emitted. In beta+ decay, a positron and an electron neutrino is emitted. In both types of decay, if the nucleus is left in an excited state, when it comes back down to ground state, it emits a photon in the form of a gamma ray. In beta+ decay that is precipitated by K Capture, the electron cloud is left in a multi level excited state, and it has one or (usually) more drops in energy as it returns to ground state, each drop emitting a photon in the form of an x-ray.
Yes
An excited electron releases a photon as it returns to ground state.
A photon will be released!
Fluorescence is produced when an electron excited by an e.m. radiation returns to the ground state and emit a photon.
It depends on the atom. For example, the electron configuration of an atom of boron in the ground state is 2-3. In the excited state, it would be 2-2-1. For an atom of chlorine, the ground state configuration is 2-8-7. The excited state would be 2-8-6-1. When an atom enters the excited state, an electron moves up to a higher energy level and releases energy. An electron in the excited state is not stable until it returns to ground state.
The amount of energy that is absorbed is the same as the amount of energy that is released.
When an electron returns to its ground state it emits energy in the form of light.
Atoms emit light energy for several reasons: Atoms emit visible light most often when an electron moves from an excited state to a less excited state. Atoms accelerating at high rates can emit bremsstrahlung, or breaking radiation. Finally, atomic nuclei in an excited state can decay to less excited states, emitting light energy. This energy usually not visible though, in the X or gamma ray spectrum.
Lots of wrong answers out there, tested this on school, the answer is: Drops from a higher to a lower energy level
Depending on the energy (frequency) of the specific photon hitting the electron, one of three events happens: nothing, the electron is excited, or the electron leaves the atom. If the energy of the photon very high, the electron can absorb the energy and escape the nucleus' pull. This is called ionization. If the energy of the photon lines up with the energy spacing in the atoms energy levels, the electron will move to a higher energy state, becoming excited. The electron then returns to its original energy level, releasing the energy as light. If the energy of the photon does not fall into one of these categories, the electron does not interact with it. In terms of actually changing the electron, it only changes in energy, not any other property.
In beta- decay, an electron and an electron antineutrino is emitted. In beta+ decay, a positron and an electron neutrino is emitted. In both types of decay, if the nucleus is left in an excited state, when it comes back down to ground state, it emits a photon in the form of a gamma ray. In beta+ decay that is precipitated by K Capture, the electron cloud is left in a multi level excited state, and it has one or (usually) more drops in energy as it returns to ground state, each drop emitting a photon in the form of an x-ray.
Yes
line emission