Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur.
We use the molar enthalpies to calculat exactly how much heat is transferred during these processes.
Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply.
3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
A physical property
heat of fusion
The first is called enthalpy of vaporization, the second is called enthalpy of fusion.
What you need is the enthalpy of fusion for ice and simply multiply it by your mass. An online search shows that the enthalpy of fusion for ice is: 79.72 cal/g So calories needed to melt all your ice is just. Energy = 79.72cal/g x 25g = 242.50 calories
Latent heat of fusion (or enthalpy of fusion) is a characteristic of a substance, rather than a chemical bond. If you mean enthalpy of reaction then the lowest absolute values are for the bonds in H2, F2, and Cl2 as gases, which are zero. One low (and negative) value is for cuprous sulphate. Please see the link.
Enthalpy is a state function, and to a first approximation does not depend on temperature. So the change in enthalpy to go from solid to a gas directly (sublimation) at some temperature is equal to the sum of the enthalpies associated with going from a solid to a liquid (fusion) and going from a liquid to a gas (vaporization) at other temperatures.
A physical property
Enthalpy of fusion/vaporization is the amount of energy added to a system to melt of boil a substance or the amount of energy removed from a system to condense or freeze a substance.
heat of fusion
The heat energy, or enthalpy, associated with a solid to liquid transition is the enthalpy of fusion and that associated with a solid to gas transition is the enthalpy of sublimation.
The first is called enthalpy of vaporization, the second is called enthalpy of fusion.
This energy is the enthalpy of fusion (or latent heat of fusion).
The latent heat of fusion
What you need is the enthalpy of fusion for ice and simply multiply it by your mass. An online search shows that the enthalpy of fusion for ice is: 79.72 cal/g So calories needed to melt all your ice is just. Energy = 79.72cal/g x 25g = 242.50 calories
It is called the enthalpy of fusion of a substance, also known as (latent) heat of fusion.
Yes, that's right.What you are referring to is called the enthalpy of fusion or the latent heat of fusion.
The Fusion is the change in enthalpy for the conversion of 1 mole or 1 gram of a solid to a liquid, at constant pressure and temperature and is usually denoted as ΔHfus.