Although the question is stated in a somewhat confusing way, we can state with
confidence that the velocity of the car is NOT uniform, because a value is given for
its acceleration. 'Uniform' motion means zero acceleration.
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
Momentum = mass x velocity. You already stated the mass and velocity so you can figure out the momentum.
No the two buses do not have equal velocities because VELOCITY is the SPEED in a given DIRECTION. One would have a velocity of +30m/s because it is traveling in one direction, and the other would have a velocity of -30m/s because it is traveling in the opposite direction.
Jack is driving a car. As he passes post 1 he is travelling at 15ms-1 and starts to accelerate at a steady speed. 8 seconds later he passes post 2 travelling at 30ms-1. Post 1 and 2 are What is his acceleration during this time?
not enough information to support it
Initial kinetic energy = 1/2 M Vi2 Final kinetic energy = 1/2 M Vf2 Difference = 1/2 M (Vf2 - Vi2) = 2,500(302 - 202) = 2,500(900 - 400) = 2,500 x 500 = 1,250,000 joules
A Lot!
The new wireless N adapter for Xbox 360 can work effectively from 50-100 feet, however, there is some notable lag-time of about 20-30ms.
Hello im 14 nd thin I work out for about 30ms a day and eat good but it doesn't seem like I'm gaining musle should I use protein
Your answer is 18 meters 30 * 0.6 = 18
we have seek = 10-50 ms so , average seek = (10+50) / 2 = 30ms and the access time = seek + latency = 20 + 30 = 50 ms
If the car and driver are moving (along a flat horizontal surface) at constant speed, then there is no acceleration, and the net horizontal force is zero.The applied 3,000N must be canceled by an effective total 3,000N of friction.