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When determining the molarity of a solution the answer must be in terms of?
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∙ 12y ago
moles per liter.
Wiki User
∙ 12y ago
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When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
A solution has OH- 3.5 x 10-6 Based on that what must be true about this solution?
It is a basic solution.
A solution that is at equilibrium must be?
Saturated
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
What is the effect on the molarity of a solution of adding more solvent to a solution?
Adding more solvent to a solution decreases the molarity of the solution. This is based on the principle that initial volume times initial molarity must be equivalent to final volume times final molarity.
How many salt is in a salt solution?
The salt content of a salt solution can be found from the solutions' molarity. Any solution with a salt content can be called a salt solution. There is no one set standard which determines the amount of salt which must be in a solution for it to be a salt solution.
How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
How do you prepare a solution of 1 M H2NO4?
It depends on how much you are trying to make and what you are diluting it from, but the formula for figuring it out is Molarity of starting solution times X (in which X is how much you will be adding) equals Molarity of the solution you are producing times its volume
Explain why it is not enough just to say that a solution is hypertonic?
hypertonic and hypotonic are relative terms. A solution that is hypertonic to tap H2O could be hypotonic to seawater. In using these terms, you must provide a comparison, as in 'the solution is hypertonic to the cells cytoplasm'.
If 1.25 grams of pure CaCO3 required 25.5 mL of a HCl solution for complete reation what is the molarity for the HCl solution?
When calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) the reaction is:- CaCO3 + 2 HCl -> CaCl2 + H2O + CO2 The weight for 1 mole of calcium carbonate is the atomic weight in grams or 40.8 + 12.011 + 3 x 15.9994 = 100.8092 grams 1.25 grams of CaCO3 is therefore 1.25/100.8092 or .0124 mole There must have been twice this many moles of HCl in the solution or 0.0248 mole. The molarity of the solution is the number of moles per litre so with 0.0248 in 25.5 ml there must be .97 mole in 1 litre. The HCl solution must therefore be .97 molar
What must you do before determining gravitational PE?
you must determine hight
What must you do first before determining gravitational PE?
you must determine hight
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
What must be taken into consideration when determining a safe speed on a boat?
The wind speed and the wave height are two things that must be taken into consideration when determining a safe speed for a boat.
A 2.14-L sample of hydrogen chloride HCl gas at 2.61 ATM and 28C is completely dissolved in 668 mL of water to form hydrochloric acid solution Calculate the molarity of the acid solution Assume n?
Using this ideal gas equation PV=nRT. The question provided the following: P=2.61 atm V=2.14L R=0.0821 ( this is standard for any ideal gas) T= 28 C+273K= 301 n= unknown Since there is no volume change, so the volume is constant from the beginning of the reaction to the the end of the reaction. The only key information we are missing is the actual number of moles (n). We must rearrange the ideal gas equation to solve for moles. n=PV/RT n=(2.61)(2.14)/(.0821)(301) n=.2260 The question wants us to find the Molarity of the acid solution. We were given that HCL completely dissolved in 668mL of water. Molarity moles/Liters. 668mL=.668L M=.2260mol/.668L so Molarity of the acidic solution is .338.
