J. K. Greye Software ended in 1984.
J. K. Greye Software was created in 1981.
%%%fim1 is our image%%% [ r c ] = size(fim1); even=zeros(r,(c/2)); %first level decomposition %one even dimension for j = 1:1:r a=2; for k =1:1:(c/2) even(j,k)=fim1(j,a); a=a+2; end end %one odd dim odd=zeros(r,(c/2)); for j = 1:1:r a=1; for k =1:1:(c/2) odd(j,k)=fim1(j,a); a=a+2; end end [ lenr lenc ]=size(odd) ; %one dim haar for j = 1:1:lenr for k =1:1:lenc fhigh(j,k)=odd(j,k)-even(j,k); flow(j,k)=even(j,k)+floor(fhigh(j,k)/2); end end %2nd dimension [len2r len2c ]=size(flow); for j = 1:1:(len2c) a=2; for k =1:1:(len2r/2) %even separation of one dim leven(k,j)=flow(a,j); heven(k,j)=fhigh(a,j); a=a+2; end end %odd separtion of one dim for j = 1:1:(len2c) a=1; for k =1:1:(len2r/2) lodd(k,j)=flow(a,j); hodd(k,j)=fhigh(a,j); a=a+2; end end %2d haar [ len12r len12c ]=size(lodd) ; for j = 1:1:len12r for k =1:1:len12c %2nd level hh f2lhigh(j,k)=lodd(j,k)-leven(j,k); %2nd level hl f2llow(j,k)=leven(j,k)+floor(f2lhigh(j,k)/2); %2nd level lh f2hhigh(j,k)=hodd(j,k)-heven(j,k); %2nd level ll f2hlow(j,k)=heven(j,k)+floor(f2hhigh(j,k)/2); end end % level=level-1;
while(1) { // thread i (0 <= i < n) for (j=1 ; j<n ; j++) { flag[i]=j; last[j]=i; for (k=0 ; k<n ; k++) { if (k==i) continue; while (flag[k]>=flag[i] && last[j]==i) { sleep(random()); } } } // critical section ... // end of critical section flag[i]=0; // not critical section ... // end of not critical section }
There are no 13 letter words that start with J and end with K.
while(1) { // thread i (0 <= i < n) for (j=1 ; j<n ; j++) { flag[i]=j; last[j]=i; for (k=0 ; k<n ; k++) { if (k==i) continue; while (flag[k]>=flag[i] && last[j]==i) { sleep(random()); } } } // critical section ... // end of critical section flag[i]=0; // not critical section ... // end of not critical section }
that kevin new that he wasnt going to live long but he kept trying
J. K. Buckle has written: 'Managing software projects' -- subject(s): Computer programming, Computer programming management, Management
K j equals j when K is 1 or j is 0.
J and K
K comes after J.
j for attack k for defend and l for jump bat s+k+j leamasex j+k+l+j+k+l+s+j+k
taking an example of matrix x ,we find whether this matrix is transitive or not: x=[1 1 0 ;1 0 1;1 0 1] m=1; for i=1:3 for j=1:3 if x(i,j)==1 for k=1:3 if x(j,k)==1 if x(i,k)~=1 m=0; end end end end end end if m==1 disp('Given matrix is Transitive') else disp('Given Matrix is not Transitive') end