Water is the solvent.
Not completely sure what you're asking, but copper sulfate (CuSO4) will dissolve easily in water to form a cool-looking blue colored solution.(The term is dissolve).
strange question but the sand sinks and falls to the bottom of the water, ti wll never ever dissolve in water but just sinks to the base of a beaker
Use really clean equipment. Heat some water in a beaker so that it will dissolve more solute. Dissolve all that it will hold, to make sure add excess. Decant the liquid into another beaker allow no crystals to be transferred to the new beaker. Allow to cool slowly. Do not agitate. The cool solution will be supersaturated.
The volume of the water in Beaker X will be 100cm3, as you are not adding any more water to the equation (50X+100Y is not 150Y or X, but 50X+100Y) The total volume of matter in Beaker X will be 150cm3, and if the beaker is labelled, the volume measure will indicate 150cm3 due to the displacement of water. But as the answer to your question, the volume of water in Beaker X must be 100cm3 even though visual indicators will not show this due to the displacement of water by marbles
when ice cubes place in the beaker, outside of the beaker have a formation of water drops. by. JD
Put them in a beaker. Add water to the mixture. Agitate to insure dissolution. Centrifuge the colloidal suspension. Pour off the water into a different beaker and heat to 100C. Salt will be in the beaker where water was after complete evaporation. Sand will be in the other after drying. Sand doesn't dissolve in water. Salts do.
Use really clean equipment. Heat some water in a beaker so that it will dissolve more solute. Dissolve all that it will hold, to make sure add excess. Decant the liquid into another beaker allow no crystals to be transferred to the new beaker. Allow to cool slowly. Do not agitate. The cool solution will be supersaturated.
the lump of sugar will slowly dissolve and undergo osmosis, if you stir or swirl the beaker it this will happen much faster
The temperature will decrease
Not completely sure what you're asking, but copper sulfate (CuSO4) will dissolve easily in water to form a cool-looking blue colored solution.(The term is dissolve).
The temperature of the solution decreases
the temperature of the solution decreases.
when the hot water in the beaker touches the cool surface of the beaker,the water condenses into water droplets.
strange question but the sand sinks and falls to the bottom of the water, ti wll never ever dissolve in water but just sinks to the base of a beaker
Beaker A: 15 C Beaker B: 37 C Beaker B contains water molecules that have the greater kinetic energy (on average). Since beaker B is at a higher temperature than beaker A, the water molecules must be moving faster in beaker B than in beaker A (on average). If heat is being applied to the beakers, then the increased amount of heat applied to beaker B is greater, and the heat will cause the water molecules in beaker B to move faster than the water molecules in beaker A (on average). Kinetic energy = (1/2) (mass) (velocity)^2 Since the velocity of the a water molecule in beaker B is on average greater than the velocity of an average water molecule in beaker A, the water in beaker B has a higher kinetic energy.
If you mean seperate: Use a bunsen burner, a tripod, and a beaker. Place the beaker onto the tripod which should be on top of the bunsen burner. Pour the salt/sand water into the beaker and turn the bunsen burner onto the safety flame. Then put the beaker on the tripod, and wait for the water to evaporate.
Use really clean equipment. Heat some water in a beaker so that it will dissolve more solute. Dissolve all that it will hold, to make sure add excess. Decant the liquid into another beaker allow no crystals to be transferred to the new beaker. Allow to cool slowly. Do not agitate. The cool solution will be supersaturated.