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What else can I help you with?
How do you get Pseudo code for largest element of an array?
Pseudocode: if x > y then return x else return y Actual code (C++): return( x>y ? x : y );
To find the greatest among two numbers using only if condition and not else?
int Greatest(int X, int Y){if(X > Y)return X;return Y;}
Is there an algorithm which accepts two numbers from the user and displays which of the two numbers are relatively greater?
Algorithm:Given x and y are both numbers, if x is greater than y then return x, otherwise return y.C++ implementation of the algorithm:template T GetMax(T x, T y) { return(x>y?x:y); }
What is the loop equivalent code for javascript?
dataBase[0].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[0].columnline]); }); dataBase[1].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[1].columnline]); }); dataBase[2].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[2].columnline]); }); dataBase[3].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[3].columnline]); }); dataBase[4].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[4].columnline]); }); dataBase[5].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[5].columnline]); }); dataBase[6].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[6].columnline]); }); dataBase[7].valueline = d3.svg.line() .x(function(d) { return x(d["Date"]); }) .y(function(d) { return y(d[dataBase[7].columnline]); }); I am trying to make a javascript loop that would do the same, but whenever I replace the counter with the numbers, it doesn't work.
Write a program that will add the number specified by the user?
In BASIC, this could be as simple as: 10 Input X 20 Input Y 30 Z=X+Y 40 Print X;" + ";Y;" = ";Z 50 END In JAVA... /** * A simple calculator that adds, subtracts, multiplies, and divides. * Written in Java by: AustinDoggie */ public class Calculator() { public Calculator() { // don't really have to do anything here } public int add(int x, int y) { int z = x + y; // add two numbers return z; // and return it } public int subtract(int x, int y) { int z = x - y; // subtract two number return z; // and return it } public int multiply(int x, int y) { int z = x*y; // multiply two number return z; // and return it } public int divide(int x, int y) { int z = x/y; // divide two numbers return z; // and return the result } } Hope that helps.
How do you find and return the minimum and maximum of two values using macrosand ternary operator?
#define MIN(x,y) ((x<y)?x:y) #define MAX(x,y) ((x>y)?x:y)
What is return keyword in c?
return lets you literally return a value from a function. This allows you to define functions like: int add(int x, int y) { return(x + y); } int twoplustwo = add(2, 2);
Write java program to find x to the power y use overloding for defferenc case when x and y combniation of integer and floating point number?
// integer version - returns xypublic static final long power(final long x, final long y) {// special case for 0if(y == 0) {return 1;}long exp = x;// loop solution - for the sake of simplicityfor(long i = 1; i < y; ++i) {exp *= x;}return exp;}// floating point version - returns xypublic static final double power(final double x, final double y) {// special case for 0if(y == 0) {return 1;}double exp = x;// loop solution - for the sake of simplicity// note: this will NOT work for fractional numbersfor(long i = 1; i < y; ++i) {exp *= x;}return exp;}
Algorithm to count the digits in a given number?
def digits(x):""" Return amount of digits of x. """y = math.log10(x)if y % 1 0:return int(y)else:return int(math.floor(y) + 1)
Can you write a program that will read three integers and output a message telling whether exactly two of them are greater than 10?
Yes. Use the following function to determine if two of three values are greater than 10. bool f (int x, int y, int z) { if (x<=10 ) return y>10 && z>10; else if (y<=10) return x>=10 && z>10; else if (z<=10) return x>10 && y>10; return false; }
Write a program to interchange the value of two given numbers using C plus plus?
#include <iostream> using namespace std; int main() { int x=5, y=10; cout << "Before:" << endl; cout << "x=" << x << " y=" << y << endl; // swap x and y values. x ^= y ^= x ^= y; cout << "After:" << endl; cout << "x=" << x << " y=" << y << endl; return( 0 ); }
Example of Fibonacci in c plus plus?
#include<iostream> int main() { int x=0, y=1; std::cout<<x<<" "; std::cout<<y<<" "; while( y<1000000 ) { std::cout<<(y+=x)<<" "; x=y-x; } std::cout<<std::endl; return(0); }
