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When equivalent amounts of h plus and OH- have reacted in titration?
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When equivalent amounts of H and OH have reacted in titration?
When equivalent amounts of H and OH have reacted in titration, the solution is at the equivalence point. This indicates that all the acid has been neutralized by the base. At this point, the solution will have a pH of 7 if the acid and base are both strong, or slightly above or below 7 if they are not.
What is true about the amounts of H and OH at the stoichiometric point in a titration of a strong acid with a strong base?
At the stoichiometric point in a titration of a strong acid with a strong base, the amounts of H+ and OH- ions are equal. This results in a neutral solution as the acid and base have completely reacted to form water.
Discussion of titration?
Titration is the controlled addition and measurement of the amount of a solution of known concentration required to react completely with a measured amount of a solution of unknown concentration. Titration provides the equivalent volumes of acidic and basic solutions. In order to find this, MaVa/Ca formula needs to be used. In titration, when equal numbers of H3O+ and OH- from the acidic and basic solutions react, the resulting solution is neutral (water and salt). In titration, the end point would be the point at which the indicators change color; in this case the indicator turned pink. The equivalence point would the point at which the two solutions used in titration are present in chemically equivalent amounts. The indicator, phenothaylene, is used to determine the equivalence point of weak-acid/strong- base titrations.
How is the KB of ammonia calculated from the half titration point?
The KB of ammonia (NH3) can be calculated from the half-titration point by using the expression for the equilibrium constant of the reaction: KB = [NH4+][OH-]/[NH3]. At the half-titration point, half of the ammonia has been converted to ammonium (NH4+). By knowing the initial concentration of ammonia and the volume of titrant added to reach the half-titration point, you can calculate the concentration of NH4+ and OH- to determine KB.
What is the pH at the stoichiometric point of the titration of 25.0 mL of aqueous hypochlorous acid with 0.20 M KOH aq?
The stoichiometric point of the titration of hypochlorous acid (HOCl) with KOH occurs when all the acid has reacted with the base to form the salt, potassium hypochlorite (KClO). At this point, the pH is determined by the hydrolysis of the resulting salt, which forms hypochlorite ions (ClO-) and hydroxide ions (OH-). The pH at the stoichiometric point is determined by the concentration of these ions and can be calculated using the equilibrium constant for the hydrolysis reaction.
How many equivalent OH-1 are there in HC2H3O2?
There is only one equivalent of OH^-1 in one molecule of HC2H3O2.
Why does a pink color appear and then disappear quickly in the titration experiment?
Let's say that your titrant is NaOH. What happens is as there are OH- ions present the color changes into a pinkish hue, but the color disappears quickly because the H+ ions present in the sol'n take the OH- ions; so there is no color until the end point really =)
Is OH a gas?
No, OH is not a gas. OH is the chemical formula for the hydroxyl radical, which is a highly reactive species that is typically found in small amounts in gases or liquids.
Calculate the theoretical yield of calcium chloride expected for this reaction if 0.80 mol of calcium hydroxide is reacted with excess hydrochloric acid.?
The balanced chemical equation for the reaction is Ca(OH)2 + 2HCl -> CaCl2 + 2H2O. Since 1 mol of Ca(OH)2 produces 1 mol of CaCl2, if 0.80 mol of Ca(OH)2 is reacted, the theoretical yield of CaCl2 is also 0.80 mol.
Why you use oxalate potassium in formol titration?
In formol titration, amino acids with formaldehyde are titrated with NaOH to measure the amount of amino acids in the solution. Potassium is also necessary for this titration and is supplied by using potassium oxalate. If calcium is present, it will react with the NaOH to form Ca(OH)2. This will make it appear to need more of the NaOH solution (and overestimate the titration). Potassium oxalate will chelate the calcium, and prevent it from reacting (forming calcium oxalate).
How is lime formed?
Quick lime is obtained by heating (calcining) calcium carbonate. If the CaO obtained is reacted with water it produces slaked lime Ca(OH)2
