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When K_a is close to the molarity of the reactants you can use successive approximtions as opposed to the quadratic formula.

You simply ignore the value of x being subtracted from the reactants to find the value of x.

This will give you an answer which you then plug back into the equation in place of the x value you initially ignored.

If you repeat this procedure of plugging each new answer back in for x, you will find that the answer will begin to become closer and closer to the same value: This is the actual value of x.

This should be the initial set up for this type of problem:

K_a = some x value (ie. x^2) / (concentration - x)(concentration - x)

The K_a value will be given.

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1w ago

The method of successive approximations is often used in solving acid-base equilibrium problems that involve complex calculations and iterative processes. By making an initial assumption for the concentration of a particular species, performing calculations based on that assumption, and then refining the concentration through successive iterations, a more accurate solution can be obtained. This method is particularly useful when analytical solutions are difficult to derive directly.

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