Want this question answered?
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
range
The type of motion that describes the horizontal component of a projectile is horizontal projectile motion. It is influenced by the downward force of gravity.
Do you really mean minimum distance? This would be achieved if the projectile went straight up and down, ie 90 deg from horizontal. Maximum distance would be obtained at 45 deg to horizontal.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
45 degrees.
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
15.42 degrees
The range of projectile is maximum when the angle of projection is 45 Degrees.
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
A baseball, cannonball, or other projectile launched at a 45° angle above the horizon will achieve maximum horizontal range. A projectile launched straight up will achieve maximum altitude, but you kind of have to watch it and be careful when it returns.
The half maximum range of a projectile is launched at an angle of 15 degree
The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
The weight and shape of the bullet, the speed at which the bullet leaves the gun, and the degree of tilt of the barrel above the horizontal.
Are you asking about the maximum effective range or the maximum range that a 22 short projectile can travel?
range