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A projectile has maximum horizontal range when it is launched at an angle of 45 degrees to the horizontal. This angle allows for the ideal balance between the horizontal and vertical components of the projectile's velocity, ensuring that it travels the farthest distance before hitting the ground.
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What is the word for the horizontal distance a projectile travels?
The horizontal distance a projectile travels is called range.
What is the proof that 45 degrees provides the maximum range for projectile motion?
The proof that 45 degrees provides the maximum range for projectile motion is based on the fact that at this angle, the horizontal and vertical components of the initial velocity are equal. This results in the projectile traveling the farthest distance before hitting the ground.
In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
What is the formula for a horizontal launched projectile?
The formula for the horizontal distance traveled by a horizontally launched projectile is: range = initial velocity * time. This formula assumes that there is no air resistance and that the projectile is launched horizontally.
At what angle from a horizontal should a weapon be fired to achieve minimum distance traveled by the projectile?
The weapon should be fired at a 45-degree angle from the horizontal to achieve the minimum distance traveled by the projectile. This angle maximizes the range (horizontal distance) of the projectile by balancing the vertical and horizontal components of its velocity. At any other angle, the total distance traveled would be greater.
Under what conditions will a projectile travel maximum range?
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
The angle of projection of a projectile for which the horizontal range and maximum height are equal?
45 degrees.
What is the word for the horizontal distance a projectile travels?
The horizontal distance a projectile travels is called range.
A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height What is the angle of projection?
15.42 degrees
The range of projectile is maximum when the angle of projection is?
The range of projectile is maximum when the angle of projection is 45 Degrees.
What is the proof that 45 degrees provides the maximum range for projectile motion?
The proof that 45 degrees provides the maximum range for projectile motion is based on the fact that at this angle, the horizontal and vertical components of the initial velocity are equal. This results in the projectile traveling the farthest distance before hitting the ground.
What is maximum rang of projectile motion?
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
What is the angle for maxium altitude?
A baseball, cannonball, or other projectile launched at a 45° angle above the horizon will achieve maximum horizontal range. A projectile launched straight up will achieve maximum altitude, but you kind of have to watch it and be careful when it returns.
At what launch angle or angles will the projectile land at half of its maximum possible range?
The half maximum range of a projectile is launched at an angle of 15 degree
Why a small departure from 45 degree landing angle can reduce the horizontal range?
The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
What factor affects a firearm's maximum projectile range?
The weight and shape of the bullet, the speed at which the bullet leaves the gun, and the degree of tilt of the barrel above the horizontal.
