Yes.
The dot product of two perpendicular vectors is 0. a⋅b = |ab|cos θ where: |a| = length of vector a |b| = length of vector b θ = the angle between the vectors. If the vectors are perpendicular, θ = π/2 radians → cos θ = cos(π/2) = 0 → a⋅b = |a| × |b| × 0 = 0 ----------------------------------------------------------------------------- The dot product can also be calculated for vectors of n dimensions as the sum of the products of the corresponding elements: a = (a1, a2, ..., an) b = (b1, b2, ..., bn) a⋅b = Σ ar × br for r = 1, 2 , ..., n With perpendicular vectors this sum is zero,
No, the sum of two vectors cannot be a scalar.
resultant
'Orthogonal' just means 'perpendicular'. You can establish that if neither vector has a component in the direction of the other one, or the sum of the squares of their magnitudes is equal to the square of the magnitude of their sum. If you have the algebraic equations for the vectors in space or on a graph, then they're perpendicular if their slopes are negative reciprocals.
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
The sum and difference of two perpendicular vectors are the same in length, but are not perpendicular unless the vectors are the same size. If they are the same size they are perpendicular, other wise they are not perpendicular.
The dot product of two perpendicular vectors is 0. a⋅b = |ab|cos θ where: |a| = length of vector a |b| = length of vector b θ = the angle between the vectors. If the vectors are perpendicular, θ = π/2 radians → cos θ = cos(π/2) = 0 → a⋅b = |a| × |b| × 0 = 0 ----------------------------------------------------------------------------- The dot product can also be calculated for vectors of n dimensions as the sum of the products of the corresponding elements: a = (a1, a2, ..., an) b = (b1, b2, ..., bn) a⋅b = Σ ar × br for r = 1, 2 , ..., n With perpendicular vectors this sum is zero,
resultant vector is a vector which will have the same effect as the sum of all the component vectors taken together.
Vectors. A scalar times a vectro is a vector. A vector times a vector is a scalr if the vectros are parallel v1.v2 = scalar. A vector times a vector is a vector if the vectors are perpendicular. Other wise a vectro times a vector is both a scalr and a vector, v1v2 = -v1.v2 + v1xv2 = -v1v2cos(x) + vqv2sin(x). If cos(x) =0 then perpendicular if sin(x)=0 then parallel. In general the product of two vectors is a quaternion the sum of a scalar and a vector. The Universe is composed of quaternions. Science and Physics has failed to appreciate that the numbes of the universe are quaternions, the sum of a scaltr and a vector. Hamilton invented quaternions in 1843.
No, the sum of two vectors cannot be a scalar.
resultant
'Orthogonal' just means 'perpendicular'. You can establish that if neither vector has a component in the direction of the other one, or the sum of the squares of their magnitudes is equal to the square of the magnitude of their sum. If you have the algebraic equations for the vectors in space or on a graph, then they're perpendicular if their slopes are negative reciprocals.
The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
An easy way to visual this is by drawing a triangle with the vectors. Obviously one vector will be the vertical and another will be perpendicular to that, the horizontal. These two vectors will connect at the ends. Then you connect the other two ends with another vector and that is the resultant. Vector sum, or the square root of the sum of the squares; you use the pythagorem theorem to find the resultant, also the hypotenuse. r2= v12 + v22. The vertical vector squared plus the horizontal squared, you take the root of the sum of the squared vectors and that gives the resultant vector. If the horizontal or vertical vector is negative, then the resultant vector will be negative as well. This is used for any units including velocity, distance, and acceleration.
A resultant Vector.
With three vectors spaced 120 degrees apart and with identical magnitudes the vector sum will be 0.
yes ithape ens only if the two vectors are perpendicular to eachothe we can equate their squares