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Remember the formula used to calculate the gravitational potential energy of a mass given its mass and height above an arbitrary zero level isPEgravity = mghWhen a pendulum is pulled back from equilibrium through an angle θ, its height is calculated with the formulah = L - L cos θwhere θ is the angular displacementThe formula used to calculate the kinetic energy of a massive particle isKE = ½ mv2In the absence of non-conservative forces, such as friction or applied, external forces, the mechanical energy in a system is conserved. That isDuring the swing of a simple pendulum, when does the bob possess maximum PE?PE is maximum at the endpoints (maximum amplitude)During the swing of a simple pendulum, when does the bob possess maximum KE?KE is maximum at equilibrium (bottom position)During the swing of a simple pendulum, what is the magnitude of the bob's maximum velocity?Another way of looking at conservation of energy is with the following energy diagram. As you can see,the "purple" curve represents the pendulum bob's KE which during each cycle begins with an initial value of zero, increases to a maximum value, and then returns to zerothe "green" curve represents the PE of the bob which begins each cycle at a maximum value, then becomes zero as the bob passes through its equilibrium position, and returns to its maximum valuethe "brown" line represents the total energy of the pendulum bob that always remains constantIf a pendulum is initially released at an angle of 37º, at what angle will its PE and the KE be equal?25.9ºRefer to the following information for the next question.At any intermediate position during the oscillation, the pendulum bob would have both PE and KE.PEmax = PEintermediate + KEintermediate = KEmaxIf the pendulum was released at point A, derive an expression for the pendulum's instantaneous velocity at point B, an intermediate position in its swing.See the related lesson on vertical circles if you are asked to calculate the tension of the string during the pendulum's oscillation. Remember that a pendulum is merely the bottom half of a vertical circle! These conservation of energy methods are the easiest way to determine an object's speed so that tensions can be calculated.
1- Walking: Some aspects of walking can be analyzed in terms of the simple harmonic motion of a pendulum. The motion of one foot in each step can be considered as approximately a half-cycle of a simple harmonic motion. 2- Energy Expended in Running: During each step of the run, the leg is accelerated to a maximum angular velocity ωmax. In our pendulum model, this maximum angular velocity is reached as the foot swings past the vertical position =0. 3- Carrying Loads.
A pendulum oscillates between two stationary points at the ends of its swing, with maximum speed at the center of the swing. So the kinetic energy is highest at the swing center where it is travelling fastest, and drops to zero at the stationary end points. The potential energy does the opposite, being a maximum at the ends and minimum in the center.
make shorter length
During the half-arc when the pendulum bob is falling toward the center, gravity is doing work on it ... exerting a force which moves through a distance ... and adding to its kinetic energy. During the other half, when the bob is moving up from the center, it's using its own kinetic energy to work against gravity. That moves it to a higher elevation, adding to its gravitational potential energy, and placing it in a position from which it can fall again.
maximum or peak value
Remember the formula used to calculate the gravitational potential energy of a mass given its mass and height above an arbitrary zero level isPEgravity = mghWhen a pendulum is pulled back from equilibrium through an angle θ, its height is calculated with the formulah = L - L cos θwhere θ is the angular displacementThe formula used to calculate the kinetic energy of a massive particle isKE = ½ mv2In the absence of non-conservative forces, such as friction or applied, external forces, the mechanical energy in a system is conserved. That isDuring the swing of a simple pendulum, when does the bob possess maximum PE?PE is maximum at the endpoints (maximum amplitude)During the swing of a simple pendulum, when does the bob possess maximum KE?KE is maximum at equilibrium (bottom position)During the swing of a simple pendulum, what is the magnitude of the bob's maximum velocity?Another way of looking at conservation of energy is with the following energy diagram. As you can see,the "purple" curve represents the pendulum bob's KE which during each cycle begins with an initial value of zero, increases to a maximum value, and then returns to zerothe "green" curve represents the PE of the bob which begins each cycle at a maximum value, then becomes zero as the bob passes through its equilibrium position, and returns to its maximum valuethe "brown" line represents the total energy of the pendulum bob that always remains constantIf a pendulum is initially released at an angle of 37º, at what angle will its PE and the KE be equal?25.9ºRefer to the following information for the next question.At any intermediate position during the oscillation, the pendulum bob would have both PE and KE.PEmax = PEintermediate + KEintermediate = KEmaxIf the pendulum was released at point A, derive an expression for the pendulum's instantaneous velocity at point B, an intermediate position in its swing.See the related lesson on vertical circles if you are asked to calculate the tension of the string during the pendulum's oscillation. Remember that a pendulum is merely the bottom half of a vertical circle! These conservation of energy methods are the easiest way to determine an object's speed so that tensions can be calculated.
1- Walking: Some aspects of walking can be analyzed in terms of the simple harmonic motion of a pendulum. The motion of one foot in each step can be considered as approximately a half-cycle of a simple harmonic motion. 2- Energy Expended in Running: During each step of the run, the leg is accelerated to a maximum angular velocity ωmax. In our pendulum model, this maximum angular velocity is reached as the foot swings past the vertical position =0. 3- Carrying Loads.
A pendulum oscillates between two stationary points at the ends of its swing, with maximum speed at the center of the swing. So the kinetic energy is highest at the swing center where it is travelling fastest, and drops to zero at the stationary end points. The potential energy does the opposite, being a maximum at the ends and minimum in the center.
make shorter length
That depends on the period of the clock's pendulum. If we assume it's one second, then it does 1800 cycles in half an hour.
You are, presumably, referring to alternating current, in which case the 'maximum' current is the peak or amplitude of the waveform. The 'average' value of current is zero, because the average value of the first half of each cycle is negated by the average value over the second half of each cycle. This is why a.c. currents and voltages are always expressed in 'root-mean-square' (r.m.s.) values which is the value of an a.c. current that does the same amount of work as a given value of d.c. current. The r.m.s. value for a sinusoidal current (and voltage, as voltage and current are proportional) is 0.707 times the peak or maximum value.
Presumably you are referring to an a.c. current?If so, then the average value of an a.c. current is zero so, clearly, you cannot determine its maximum value.However, average current is more-usually applied over half a cycle, in which case, for a sinusoidal current, this value is 0.637 Imax. So the maximum current will be the average value, divided by 0.637.
The bandwidth is the difference between the frequencies at which the average power dissipated is one half the maximum value or current is 1/square root(2) times its maximum value. One frequency is greater than and the other is smaller than resonant frequency and they are symmetrical about it.
The half maximum range of a projectile is launched at an angle of 15 degree
Because the value of it is worth half the value of a dime.
Use the formula t = 2*pi*sqrt(l/g)