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What is the effect of doubling the intensity of light on the number of electrons being emitted from a metal?
Wiki User
∙ 12y ago
Visible light of a different frequency is a different color. Visible light of a higher
frequency is closer to the violet end of the spectrum.
If the frequency of a light source were increased, then the wavelength of its
emission would decrease, because the product of (frequency) x (wavelength)
is always the same number for all light in the same medium.
Wiki User
∙ 10y ago
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The wave model of light does not explain what?
It does not explain the photoelectric effect. According to the wave theory, given light of sufficient intensity, electrons should be emitted from the surface of a metal. What is observed though, is that given light of sufficient frequency, electrons will be emitted from the metal surface independent of intensity. If the frequency is too low, electrons will NOT be emitted even if the highest intensity of light was used. Albert Einstein suggested that it would be possible to explain the photoelectric effect if light was considered to be made up of particles instead of waves. The energy of the particles of light, called photons, would be proportional to the frequency of the light. Electrons would be emitted from the metal only if the energy of ONE photon was sufficient for the electron on the metal surface to break bonds and escape from the surface. Otherwise, the photons will rebound on the metal surface with no emission of electrons. Einstein 'mathematised' the photoelectric effect in the following equation: hf = Ekmax + o where h is the planck constant f is the frequency of the radiation Ekmax is the maximum kinetic energy of the emitted electrons o is the work-function energy, that is the minimum energy required for the electron to escape from the metal surface. Note: hf is the energy of a photon. It was for the explanation of the photoelectric effect that Einstein was awarded the Nobel prize in Physics in 1921. (and not for his still greater discoveries in relation to relativity)
What is the effect of frequency of incident light on photoelectric current?
The photoelectric effect is based on two principles. 1. The intensity or brightness of the visible light (number of photons): The higher the intensity (larger number of photons) determines the number of electrons that are released from the surface material. 2. The frequency of visible light (wavelength): The higher the frequency a beam of light has when it strikes the surface determines the speed (kinetic energy) of the electrons that are ejected from the material. This is independent from light intensity. The higher the frequency of the light, the higher the energy of the electrons emitted, and thus, the higher the current of the circuit.
What is pv effect?
In the photoelectric effect, electrons are emitted from matter (metals and non-metallic solids, liquids or gases) as a consequence of their absorption of energy from electromagnetic radiation of very short wavelength, such as visible or ultraviolet light. Electrons emitted in this manner may be referred to as "photoelectrons"
How traffic signals use photoelectric effect?
The photoelectric effect occurs when electrons are emitted after they absorb light. This helps traffic lights function and shine more brightly.
Which would have greater effect on kinetic energy of an object doubling the mass or doubling the velocity?
the velocity is decreased
Effect of intensity?
The photoelectric current is directly proportional to intensity.It also depends upon frequency, but frequency more than "THRESHOLD FREQUENCY" does not effect the current.The no. of electrons emitted per second by a photo-sensitive surface is directly proportional to the intensity of the incident radiations.So,the photoelectric current depends upon the intensity of the incident radiations.
The wave model of light does not explain what?
It does not explain the photoelectric effect. According to the wave theory, given light of sufficient intensity, electrons should be emitted from the surface of a metal. What is observed though, is that given light of sufficient frequency, electrons will be emitted from the metal surface independent of intensity. If the frequency is too low, electrons will NOT be emitted even if the highest intensity of light was used. Albert Einstein suggested that it would be possible to explain the photoelectric effect if light was considered to be made up of particles instead of waves. The energy of the particles of light, called photons, would be proportional to the frequency of the light. Electrons would be emitted from the metal only if the energy of ONE photon was sufficient for the electron on the metal surface to break bonds and escape from the surface. Otherwise, the photons will rebound on the metal surface with no emission of electrons. Einstein 'mathematised' the photoelectric effect in the following equation: hf = Ekmax + o where h is the planck constant f is the frequency of the radiation Ekmax is the maximum kinetic energy of the emitted electrons o is the work-function energy, that is the minimum energy required for the electron to escape from the metal surface. Note: hf is the energy of a photon. It was for the explanation of the photoelectric effect that Einstein was awarded the Nobel prize in Physics in 1921. (and not for his still greater discoveries in relation to relativity)
What is the effect of frequency of incident light on photoelectric current?
The photoelectric effect is based on two principles. 1. The intensity or brightness of the visible light (number of photons): The higher the intensity (larger number of photons) determines the number of electrons that are released from the surface material. 2. The frequency of visible light (wavelength): The higher the frequency a beam of light has when it strikes the surface determines the speed (kinetic energy) of the electrons that are ejected from the material. This is independent from light intensity. The higher the frequency of the light, the higher the energy of the electrons emitted, and thus, the higher the current of the circuit.
What is pv effect?
In the photoelectric effect, electrons are emitted from matter (metals and non-metallic solids, liquids or gases) as a consequence of their absorption of energy from electromagnetic radiation of very short wavelength, such as visible or ultraviolet light. Electrons emitted in this manner may be referred to as "photoelectrons"
How traffic signals use photoelectric effect?
The photoelectric effect occurs when electrons are emitted after they absorb light. This helps traffic lights function and shine more brightly.
Which would have greater effect on kinetic energy of an object doubling the mass or doubling the velocity?
the velocity is decreased
What effects the cylinder more doubling the radius or doubling the height?
They both have the same effect on the surface area of the pipe, but the radius has more effect on its volume/capacity.
What would be the effect of resistance of a conductor of doubling its diameter?
doubles
A change in a objects speed has a what effect on its kinetic energy than a change in mass?
Doubling the speed. This is because the (non-relativistic) kinetic energy is proportional to the square of the speed.
Does the moon effect the intensity of a hurricane?
No
What is the relationship between intensity and frequency?
I assume you are asking in regard to the photoelectric effect. The intensity of the photons can be viewed as the brightness of the light. However, the frequency is the number of wavelengths that pass a certain point in a second. The frequency is also used to determine the energy of the photon (E=hf).
Fort what topic did Albert Einstein win the Nobel prise for physics?
Albert Einstein won the Nobel Prize in Physics for his explanation of the photoelectric effect. The photoelectric effect is a phenomenon in which electrons can be emitted from a material when light of certain frequencies are shined onto the material.
