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What is the effect of doubling the intensity of light on the number of electrons being emitted from a metal?
Visible light of a different frequency is a different color. Visible light of a higher
frequency is closer to the violet end of the spectrum.
If the frequency of a light source were increased, then the wavelength of its
emission would decrease, because the product of (frequency) x (wavelength)
is always the same number for all light in the same medium.
What else can I help you with?
How does the intensity of light affect the electrons emitted from a metal?
Increasing the intensity of light results in more photons hitting the metal surface, which can increase the number of electrons emitted through the photoelectric effect. This can lead to a higher current of ejected electrons being generated.
What does light do in photoeletric effect?
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
When light is incident on a metal surface it emits electrons What happens if the intensity of light increases?
If the intensity of light increases, more photons will be incident on the metal surface, leading to a higher rate of electron emission through the photoelectric effect. This results in a higher current of emitted electrons.
The wave model of light does not explain what?
It does not explain the photoelectric effect. According to the wave theory, given light of sufficient intensity, electrons should be emitted from the surface of a metal. What is observed though, is that given light of sufficient frequency, electrons will be emitted from the metal surface independent of intensity. If the frequency is too low, electrons will NOT be emitted even if the highest intensity of light was used. Albert Einstein suggested that it would be possible to explain the photoelectric effect if light was considered to be made up of particles instead of waves. The energy of the particles of light, called photons, would be proportional to the frequency of the light. Electrons would be emitted from the metal only if the energy of ONE photon was sufficient for the electron on the metal surface to break bonds and escape from the surface. Otherwise, the photons will rebound on the metal surface with no emission of electrons. Einstein 'mathematised' the photoelectric effect in the following equation: hf = Ekmax + o where h is the planck constant f is the frequency of the radiation Ekmax is the maximum kinetic energy of the emitted electrons o is the work-function energy, that is the minimum energy required for the electron to escape from the metal surface. Note: hf is the energy of a photon. It was for the explanation of the photoelectric effect that Einstein was awarded the Nobel prize in Physics in 1921. (and not for his still greater discoveries in relation to relativity)
What do scientist using classical Newtonian expect to observe during a photoelectric effect?
Scientists using classical Newtonian physics would expect to observe a gradual increase in the kinetic energy of emitted electrons when exposed to increasing light intensity in the photoelectric effect. They would also expect the emission of electrons to start immediately upon exposure to light, regardless of its frequency.
How does the intensity of light affect the electrons emitted from a metal?
Increasing the intensity of light results in more photons hitting the metal surface, which can increase the number of electrons emitted through the photoelectric effect. This can lead to a higher current of ejected electrons being generated.
What does light do in photoeletric effect?
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
How many electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent?
The number of electrons emitted when calcium is flashed with light of a certain wavelength and intensity depends on the photoelectric effect, which is related to the energy of the photons hitting the metal. Without the energy of the photons and the work function of calcium, we cannot determine the number of electrons emitted.
When light is incident on a metal surface it emits electrons What happens if the intensity of light increases?
If the intensity of light increases, more photons will be incident on the metal surface, leading to a higher rate of electron emission through the photoelectric effect. This results in a higher current of emitted electrons.
Effect of intensity?
The photoelectric current is directly proportional to intensity.It also depends upon frequency, but frequency more than "THRESHOLD FREQUENCY" does not effect the current.The no. of electrons emitted per second by a photo-sensitive surface is directly proportional to the intensity of the incident radiations.So,the photoelectric current depends upon the intensity of the incident radiations.
How many electrons are emitted when calcium is flashed with light of wavelength 340nm and intensity of 50 percent?
This question can likely be answered using the formula E=hc/w where w is wavelength, h is Planck's constant, c is the speed of light, and E is energy in Joules. 5 electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent.
What is the relationship between the kinetic energy of ejected electrons and the intensity of incident light in the photoelectric effect?
In the photoelectric effect, the kinetic energy of ejected electrons is directly proportional to the intensity of the incident light. This means that higher intensity light results in higher kinetic energy of the ejected electrons.
The wave model of light does not explain what?
It does not explain the photoelectric effect. According to the wave theory, given light of sufficient intensity, electrons should be emitted from the surface of a metal. What is observed though, is that given light of sufficient frequency, electrons will be emitted from the metal surface independent of intensity. If the frequency is too low, electrons will NOT be emitted even if the highest intensity of light was used. Albert Einstein suggested that it would be possible to explain the photoelectric effect if light was considered to be made up of particles instead of waves. The energy of the particles of light, called photons, would be proportional to the frequency of the light. Electrons would be emitted from the metal only if the energy of ONE photon was sufficient for the electron on the metal surface to break bonds and escape from the surface. Otherwise, the photons will rebound on the metal surface with no emission of electrons. Einstein 'mathematised' the photoelectric effect in the following equation: hf = Ekmax + o where h is the planck constant f is the frequency of the radiation Ekmax is the maximum kinetic energy of the emitted electrons o is the work-function energy, that is the minimum energy required for the electron to escape from the metal surface. Note: hf is the energy of a photon. It was for the explanation of the photoelectric effect that Einstein was awarded the Nobel prize in Physics in 1921. (and not for his still greater discoveries in relation to relativity)
What do scientist using classical Newtonian expect to observe during a photoelectric effect?
Scientists using classical Newtonian physics would expect to observe a gradual increase in the kinetic energy of emitted electrons when exposed to increasing light intensity in the photoelectric effect. They would also expect the emission of electrons to start immediately upon exposure to light, regardless of its frequency.
What happens to electrons in the photo electric effect?
Electrons are ejected from a metal surface when it is exposed to light of sufficient energy. This phenomenon is known as the photoelectric effect. The energy of the incident light is absorbed by the electrons, causing them to be emitted from the metal surface.
Will exposure to blue light cause electrons to be emitted from cesium?
Yes, exposure to blue light can cause the photoelectric effect in cesium, leading to the emission of electrons. Blue light has enough energy to overcome the work function of cesium, which allows electrons to be emitted from its surface.
What device is known when electrons are emitted when light shines on a metal surface?
The device you are referring to is a photoelectric cell or a photodiode. When light shines on the metal surface of these devices, electrons are emitted in a process called the photoelectric effect, which generates an electric current.
