5 electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent.
the intensity of radiation emitted at that wavelength, giving a characteristic spectral distribution that depends only on the temperature of the object emitting the light.
Yes, as the wavelength of the ultraviolet waves increases, the intensity of the infrared waves emitted by the Sun tends to decrease. This is because different wavelengths of electromagnetic radiation are emitted at different intensities by the Sun based on its temperature and composition.
When green light is emitted, electrons are transitioning from higher energy levels to lower energy levels within an atom. This release of energy appears as light in the green wavelength range.
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
As the wavelength increases to infinity the electro-magnetic continuum take on a new base value and with no variation has no radiation to transmit. As the wavelength decreases to zero the energy packet become a massive body and therefore is no longer a radiating.
This question can likely be answered using the formula E=hc/w where w is wavelength, h is Planck's constant, c is the speed of light, and E is energy in Joules. 5 electrons are emitted when calcium is flashed with light of wavelength 340 nm and intensity of 50 percent.
Because, due to the absorption of heat energy by the calcium atom in the flame. The electrons in the atom get promoted to a higher energy level, and exist in an unstable excited state. As they are unstable and prefer to be at their normal ground state, the extra energy that the electrons absorbed to be promoted in the first place is emitted in the form of a photon, light. The light emitted from the electrons of the calcium atoms will be at a specific wavelength, which is the red light you see emitted from the flame. Because, due to the absorption of heat energy by the calcium atom in the flame. The electrons in the atom get promoted to a higher energy level, and exist in an unstable excited state. As they are unstable and prefer to be at their normal ground state, the extra energy that the electrons absorbed to be promoted in the first place is emitted in the form of a photon, light. The light emitted from the electrons of the calcium atoms will be at a specific wavelength, which is the red light you see emitted from the flame.
The unit of fluorescence intensity is known as FUs. These are unitless and instead shows the light that is emitted from the longer wavelength.
the intensity of radiation emitted at that wavelength, giving a characteristic spectral distribution that depends only on the temperature of the object emitting the light.
Yes, as the wavelength of the ultraviolet waves increases, the intensity of the infrared waves emitted by the Sun tends to decrease. This is because different wavelengths of electromagnetic radiation are emitted at different intensities by the Sun based on its temperature and composition.
Visible light of a different frequency is a different color. Visible light of a higher frequency is closer to the violet end of the spectrum. If the frequency of a light source were increased, then the wavelength of its emission would decrease, because the product of (frequency) x (wavelength) is always the same number for all light in the same medium.
Increasing the intensity of light results in more photons hitting the metal surface, which can increase the number of electrons emitted through the photoelectric effect. This can lead to a higher current of ejected electrons being generated.
Fluorescence testing typically involves exposing a sample to a specific wavelength of light, which excites the electrons in fluorescent molecules, causing them to emit light at a longer wavelength. This emitted light is then detected using a fluorescence microscope or a spectrofluorometer. The intensity and wavelength of the emitted fluorescence provide information about the concentration and characteristics of the fluorescent compounds in the sample. Proper controls and calibration are essential to ensure accurate and reliable results.
The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
When green light is emitted, electrons are transitioning from higher energy levels to lower energy levels within an atom. This release of energy appears as light in the green wavelength range.
The more energy levels the electron jumps the more energy the emitted light will have. The more energy you have the shorter wavelength there is.