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An acceleration requires an unbalanced force.
When a skydiver opens the parachute, he or she does not move upward, but rather, continues to move downward, but at a slower speed. Sometimes there is an illusion that the skydiver is moving upward, because if there are several people skydiving together, and one of them opens a parachute while the others don't, you will see the skydiver with the open parachute moving upward with relation to the other skydivers. But they are all still moving downward, they are just doing so at different speeds.
Ignoring air resistance, it's about 9.8 m/s.
Forward it is the same as the plane that he/she was jumping off. Downward it is up to 300-350 kph.
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
Skydivers land safetly so that they do not get hurt! Did you mean something else?
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
The spreading of the arms and legs slows the fall and gives the skydiver more control of the fall.
An acceleration requires an unbalanced force.
When a skydiver opens the parachute, he or she does not move upward, but rather, continues to move downward, but at a slower speed. Sometimes there is an illusion that the skydiver is moving upward, because if there are several people skydiving together, and one of them opens a parachute while the others don't, you will see the skydiver with the open parachute moving upward with relation to the other skydivers. But they are all still moving downward, they are just doing so at different speeds.
66.7 m/s2
80 m/s2 up
Ignoring air resistance, it's about 9.8 m/s.
Forward it is the same as the plane that he/she was jumping off. Downward it is up to 300-350 kph.
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
For a simple answer, we have to ignore air resistance. As the skydiver's downward momentum increases, the earth's upward momentum increases by an identical amount. The total momentum of the earth-skydiver system remains constant.
The same as that of the aircraft that he /she is in. If flying level, it would be zero.