Here is how to solve this type of problem:
Since you have 2 pieces that add up to 130 figure out what they would be if they were of equal length.
If one piece is 26 feet longer than the other that means one piece is half of 26 longer than half of 130, the other is shorter by the same amount, so...
130/2=65
26/2=13
65+13=78
65-13=52
Lets see if that adds up. 78+52=130, so that's good. 78-52=26 so that is good as well. One piece is 78 feet long, the other is 52.
Suppose the shorter piece is x feet long. Then the longer piece is x+1 feet long. The total length of the two pieces is x + (x+1) = 2x+1 feet. So 2x+1 = 9 so 2x = 8 so x = 4' and then the other piece is 5'
let the long rope length be x and the other y. Then x + y = 136 x = y + 26 y = x -26 x + x -26 = 136 2x = 162 x = 81 ft y = 55 ft
Eight longAnswer:Two-by-four is a term applied to lumber with these dimensions (in inches) for its width and depth. The pieces are available in a number of lengths (6', 8', 16') as standard lengths and as shorter and longer pieces on special order.The two-by-four is actually 1 1⁄2 in × 3 1⁄2 in (38 mm × 89 mm).
If you let x equal the short piece then 3x would be the long piece. x + 3x = 24 4x = 24 x = 6 3x = 18 So, the shorter piece would be 6 ft. and the longer piece would be 18 ft.
50" and 10" 60 = 5x + x = 6x; x = 10
piece a has a greater length than piece b (a>b)
Length of the longer piece is 5/9 of 27 feet. So, Length of longer piece = {5/(4+5)}x27 = {5/9}x27 = 15 feet.
x the length of the shorter piece 3·x the length of the longer piece x + 3·x the length of the whole board = 4·x = 76" x = 76" / 4 = 19.
Write an equation and solve it. Call the length of the shorter piece "x", in this case, the longer piece is "3x". The sum of the two is equal to 116 inches.
If a piece of wire was cut into 2 pieces in the ratio 7:8 and the shorter piece was 14cm, then the length of the longer piece will 16cm.
A 192 inch pipe is cut into two pieces. One piece is three times the length of the other. Find the length of the short piece
81
Suppose the shorter piece is x feet long. Then the longer piece is x+1 feet long. The total length of the two pieces is x + (x+1) = 2x+1 feet. So 2x+1 = 9 so 2x = 8 so x = 4' and then the other piece is 5'
Longer: 6.75ft Shorter: 6.25ft
You need to know the length of the lever and the location of the fulcrum along that length. The ratio of the lengths on either side of the fulcrum will determine the ratio of forces at either end. The length of the lever will dictate the total force possible. For a lever of length L divided into lengths a and (L - a) by the fulcrum (where a is the length of the lever between the fulcrum and the object you want to apply force to), the mechanical advantage will beM.A = (L-a)/aThe longer the lever, the bigger you can make the numerator of that fraction while keeping a unchanged.
i really dont get it
let the long rope length be x and the other y. Then x + y = 136 x = y + 26 y = x -26 x + x -26 = 136 2x = 162 x = 81 ft y = 55 ft