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John McDouall Stuart was born on September 7, 1815.
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What is John McDouall Stuart's birthday?
John McDouall Stuart was born on September 7, 1815.
When was john McDouall born?
John McDouall Stuart was born on September 7, 1815.
How old is John McDouall Stuart?
John McDouall Stuart was born on September 7, 1815 and died on June 5, 1866. John McDouall Stuart would have been 50 years old at the time of death or 199 years old today.
When did John Mcdouall Stuart live?
John McDouall Stuart was born in Scotland on 7 September 1815. He died on 5 June 1866, aged fifty years.
Where was John McDougall Stuart born?
John McDouall Stuart was born in Dysart, Fife, Scotland, on 7 September 1815.
When did John McDouall Stuart die?
John McDouall Stuart died on June 5, 1866 at the age of 50.
How old was John McDouall Stuart at death?
John McDouall Stuart died on June 5, 1866 at the age of 50.
When did john mcdouall live?
John McDouall Stuart was born in Scotland on 7 September 1815. He died on 5 June 1866, aged fifty years.
What was John McDouall Stuart's religion?
Explorer John McDougall Stuart was Christian. His denomination was Presbyterian.
How many times did John McDouall Stuart try to cross Australia?
It took John McDouall Stuart five attempts before he succeeded in crossing Australia from south to north and back again.
How many children did John McDouall Stuart?
John McDouall Stuart did not have any children. He was a Scottish Australian explorer who is known for successfully leading the first expedition to cross Australia from south to north.
Where did john mcdouall Stuart die?
He died in heath but no body knows where in heath
