If the load is connected in wye (star) and it has a neutral, then the vectorial-difference of the phase currents will flow in the neutral and there will be no problem. On the other hand, if there is no neutral, then an unbalanced load would cause unbalanced phase voltages.
By definition, a three-phase balanced load consists of three identical loads. You cannot have a balanced load with just a single load.
unbalanced three phase may difference in the megnitutde of one phase or phase may be difference
A situation in which the load in each phase is different -it could be in magnitude or in phase angle, or both.
when current are same in every phase.
each phase is within 2% of amps per phase
There is a lot of confusion amongst consumers that an Unbalanced LoadStabilizer is generally superior to a Balanced Load Stabilizer. To clarifythis myth certain fundamental principles connected with Transformersare given below:1. Definition of Balanced and Unbalanced loads:a. A Three phase Loads on a 3 phase supply system is a Balancedload because it draws equal current from each phase. Three phaseMotors, Converters; Rectifiers using 3 phase input supply arecommon examples of Balanced loads.b. A single phase / 2 phase loads on a three phase system is calledUnbalanced load. Normally Unbalanced loads have to use aneutral wire in the system. The 2 phase loads may not require aneutral.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
Yes, the minimum is three wires, usually used when the three phases are in balance, with equal currents in all three lines. In conditions when the three phases might be unbalanced, a neutral wire is added, which makes it a 3-phase 4-wire system, and the current in the neutral depends on how out-of-balance the currents in the three lines are.
Power can be calculated in each individual phase and summed together. If the voltage is supplied L-N in RMS: P = V*I. Note this will give the same answer as calculating balanced three phase power from the equation P = V*I*sqrt(3)
The neutral current in a three-phase, four-wire, a.c. unbalanced load is the phasor-sum (vector-sum) of the three phase currents. That's more-easily said than done, as the maths can be quite difficult -certainly too difficult to explain in WikiAnswers, so you should refer to a textbook which covers the topic. Probably the best approach is to use the 'a-operator', the equivalent of the 'j-operator' used for single-phase loads.
If one phase really is missing, then you have an unbalanced load.
There is a lot of confusion amongst consumers that an Unbalanced LoadStabilizer is generally superior to a Balanced Load Stabilizer. To clarifythis myth certain fundamental principles connected with Transformersare given below:1. Definition of Balanced and Unbalanced loads:a. A Three phase Loads on a 3 phase supply system is a Balancedload because it draws equal current from each phase. Three phaseMotors, Converters; Rectifiers using 3 phase input supply arecommon examples of Balanced loads.b. A single phase / 2 phase loads on a three phase system is calledUnbalanced load. Normally Unbalanced loads have to use aneutral wire in the system. The 2 phase loads may not require aneutral.
The difference between a single and a three phase online UPS is a 3 phase can supply a 100% unbalanced load on its output without affecting its performance. A single phase cannot supply a 100% unbalanced load on the output without affecting its performance.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
On a Delta 3-phase you connect the single phase loads between pairs of the 3-phases. Warning both sides of these loads will be hot! You may want to use 3 isolation transformers so that the real loads have a neutral line.On Y 3-phase you connect the single phase loads between one of the 3-phases and neutral.In each case to balance the loads, try to put similar loads on each phase (or pair of phases).
Yes, the minimum is three wires, usually used when the three phases are in balance, with equal currents in all three lines. In conditions when the three phases might be unbalanced, a neutral wire is added, which makes it a 3-phase 4-wire system, and the current in the neutral depends on how out-of-balance the currents in the three lines are.
Is the motor 3 phase? Thats what im guessing. You would get an unbalanced load across the windings of the motor, the other 2 phase's would try to compensate and ruin the windings. 3 phase motors are obviously supposed to have 3 phase input. Weather it be in star or delta. I wouldnt try and run it if i were you!
A three phase 4-wire supply that is correctly balanced has zero current in the neutral wire, which means that no power is lost in it. A three-phase 3-wire supply that is unbalanced has unnecessarily high currents in one or more wires, so again power is lost.
for 3 phase r l load phase control rectifier what is the avg value?
Power can be calculated in each individual phase and summed together. If the voltage is supplied L-N in RMS: P = V*I. Note this will give the same answer as calculating balanced three phase power from the equation P = V*I*sqrt(3)
The neutral current in a three-phase, four-wire, a.c. unbalanced load is the phasor-sum (vector-sum) of the three phase currents. That's more-easily said than done, as the maths can be quite difficult -certainly too difficult to explain in WikiAnswers, so you should refer to a textbook which covers the topic. Probably the best approach is to use the 'a-operator', the equivalent of the 'j-operator' used for single-phase loads.
It is not possible. These are my explanations. a.If the three-phase load is balance, the power per phase is P=VpIpcosѲ and the total power is P=3 VpIp cosѲ where Vp and Ip are phase voltage and phase current, respectively. However, in actual situation metering instrument (Kw or KW-hr meter) for convinience is connected to measure line voltage and line current which gives the total three-phase power P=1.732 VLIL cosѲ. The value 1.732 is the square root of 3. b. If the load is not balance it is obvious that it is not possible. I hope you are satisfied with my explanations.