x = y = 0 ?
6
x-y=0 x=y so you will use that in the other equation by substituting every y with x 2x+y=0 2x+x=0 3x=0 x=0/3 x=0 then use that in the previous equation by substituting every x with 0 x=y 0=y; y=0 finally x=0 and y=0
y = 6
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
x = y = 0 ?
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
6
x-y=0 x=y so you will use that in the other equation by substituting every y with x 2x+y=0 2x+x=0 3x=0 x=0/3 x=0 then use that in the previous equation by substituting every x with 0 x=y 0=y; y=0 finally x=0 and y=0
y = 6
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
8
y = x + 0
solve for y so if x + y = 0 then y = -x
The domain is the x values, so x = 0 to 10. The range is the y values, so y = 0 to 25.
x+y=245 x=0-245 y=0-245
36