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CuSO4.5H2O

mass 3.86 g

molar mass: 249.70 g/mol

3.86 g / 249.70 g/mol = 1.546*10-2 mol CuSO4.

Each mole CuSO4.5H2O will dissociate in 1 mole Cu2+ and 1 mole SO42-, giving total of 2 moles ions.

So 1.546*10-2 mol CuSO4 * 2 = 3.09*10-2 mole ions

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When 3.86 g of CuSO4 - 5H2O dissolves completely in water, it releases a total of 3 moles of Cu2+ ions and 3 moles of SO4^2- ions into solution. This is because for every 1 mole of CuSO4, it releases 1 mole of Cu2+ ions and 1 mole of SO4^2- ions. Additionally, the 5H2O does not release any ions as it remains as water molecules in the solution.

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Q: When you have 3.86 g of CuSO4 - 5H2O how many total moles of ions are released when each of the following samples dissolves completely in water?
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