Any object near the surface of the earth and not constrained experiences a
downward vertical acceleration of 9.8 meters (32.2 feet) per second2 because
of the mutual force of gravitational attraction between it and the earth.
Never. The acceleration is constant, from the time the ball leaves your hand
until it hits the ground. Its value is 9.8 meters /sec2 downward. . . the acceleration
of gravity.
It's the velocity of the ball that changes directions, right at the top of the arc,
where the ball stops going up and starts going down.
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What is said above is entirely correct. Here's a good way to remember this:
When you throw a ball up in the air, you have given the ball an initial velocity in the positive (up) direction. From the second the ball leaves your hand, the acceleration due to gravity constantly pulls the ball downward, slowing the upward velocity by 9.8 m/s every second. Thus, as the ball is travelling upward, the distance traveled per second continually gets shorter since the ball is slowing down. Once acceleration has slowed the ball down enough, it will stop travelling upward and start to fall back to earth. It is at this point that velocity has changed direction, as a result of the downward acceleration overpowering the upward motion of the ball.
Vertical force does. It's as simple as that.
The vertical acceleration is caused by gravity.
zero -9.8 m/s2
After being released, a ball thrown straight down from a bridge would have an acceleration of
zero
The acceleration is the acceleration of gravity, downwards, or 9.8m/s/s (32 ft/s/s). When ball is thrown straight up it has an initial velocity that is decreasing because of gravity; at the highest point velocity is zero but acceleration is always constant at gravity rate.
Its acceleration points straight down at all times after it's released.
0 m/s per second
After being released, a ball thrown straight down from a bridge would have an acceleration of
zero
The acceleration is the acceleration of gravity, downwards, or 9.8m/s/s (32 ft/s/s). When ball is thrown straight up it has an initial velocity that is decreasing because of gravity; at the highest point velocity is zero but acceleration is always constant at gravity rate.
Its acceleration points straight down at all times after it's released.
0 m/s per second
9.8 m/s (2) Squared
-- The only horizontal force on a thrown ball is the force of air resistance, so the horizontal acceleration is very small, and the horizontal speed stays almost constant. -- The vertical force on a thrown ball is the force of gravity, so the ball accelerates straight down at the acceleration of gravity. -- The result of unequal horizontal and vertical components of acceleration is a curved path.
Of course, otherwise there would no acceleration (change of velocity).
If the object is thrown upwards, the vertical acceleration is negative and the horizontal acceleration is zero.
From the time the object leaves your hand, its acceleration doesn't change at all ... it remains constant at 9.8 meters (32.2 feet) per second2 downward. Well, we have to admit that the acceleration does change to zero once the object hits the ground.
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
No, the acceleration at the highest point is never 0.