answersLogoWhite

0

Where did sakura get her ax from?

User Avatar

Anonymous

12y ago
Updated: 8/19/2019

She doesn't have one

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

What is ax times ax?

(ax)(ax) = a2 + 2ax + x2


How is a Michigan ax different from other styles of ax?

The difference is in the shape of the head of the ax.


When did Sakura Sakura - visual novel - happen?

Sakura Sakura - visual novel - happened in 2009.


What is the homonym of ax?

The homonym of "ax" is "acts." "Ax" is a tool used for chopping, while "acts" refers to actions or performances.


Who is the world's cutest sakura?

sakura kasugano not sakura haruno!!!!!!!


What is the Tagalog of ax?

Tagalog Translation of AX: palakol


What simple machine is ax?

The ax is a wedge.


Where is the battle ax from?

From the basic woodsmans ax.


What game is evil sakura in?

There is no evil Sakura. You're probably talking about inner Sakura. Sakura isn't evil.


When was Sakura Sakura - visual novel - created?

Sakura Sakura - visual novel - was created on 2009-06-26.


What is better the esp ltd ax-414 or the ax-404?

The ESP LTD AX-414.


Write a program to subtract two 16 bit numbers in microprocessor 8086?

.code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x mov bx,y ;bx=y cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp