They intersect at points (-2/3, 19/9) and (3/2, 5)
Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
They intersect at the point of: (-3/2, 11/4)
89
pythagoras
No, equations with the same slope do not intersect unless they are the same line.
b= 10
They intersect at the point of: (-3/2, 11/4)
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)
104
There is no connection between the given curves because when they are combined into a single quadratic equation the discriminant of the equation is less than zero which means they share no valid roots.
89
pythagoras
No, equations with the same slope do not intersect unless they are the same line.
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
X = √63
b= 10
b = 14324.80366
16