well, there are multiple answers since we are solving for x.
but i will do a basic, yet correct one.
you could put the parentheses around the 4 - 4x.
this will make the equation
16(4-4x) = 0.
when you divide 16 from both sides, it goes away. and you are left with
4 - 4x = 0.
then subtract 4 from both sides, and then divide both sides by -4.
you will be left with x = 1.
if you test it out
you will see that
16(4 - 4(1)) = 0 is a correct solution.
6y + (2-2)y = 6y 6(5) + (2-2)5 = 6(5) 30 + 0 = 30
-2x+16 = 0 -2x = -16 x = 8
0
It does not matter. The statement, as given, cannot be made true using only parentheses.
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
(0 x 69) 9
6y + (2-2)y = 6y 6(5) + (2-2)5 = 6(5) 30 + 0 = 30
-2x+16 = 0 -2x = -16 x = 8
Ounces in a pound.
It does not matter. The statement, as given, cannot be made true using only parentheses.
0
(0,-4)
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
If your function is 4x^2+16x+16=0 then x=-2, if it is 4x^2-16x+16=0, then x=2
0 By the multiplication property of 0, any number multiplied by 0 equals 0
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
8x + 16 = 6x -> 2x + 16 = 0 -> 2x = -16 -> x = -8