5
At -1
y=-3X the line would cross the y-axis at (0,0)
9
-5
rearrange: y = 3x - 3, which crosses the x-axis when y = 0, ie when x = 1
The line with equation crosses the y-axis at (0, 0), so the y-intercept is 0. While the line with equation x = 1 does not cross the y-axis at all (it is parallel to it), so it has no y-intercept.
y=-3X the line would cross the y-axis at (0,0)
-15
when x = -0.25
1.5
y = 5x - 2 This follows the general equation for a straight line y = mx + c. Where 'm' is the slope/gradient and 'c' is the y-intercept. At the point the line crosses the y-axis , then x = 0 Hence y = 5(0) - 2 y = -2 is the point the line intercept the y-axis.
9
-5
rearrange: y = 3x - 3, which crosses the x-axis when y = 0, ie when x = 1
The line with equation crosses the y-axis at (0, 0), so the y-intercept is 0. While the line with equation x = 1 does not cross the y-axis at all (it is parallel to it), so it has no y-intercept.
at y=6.Make x==0 // then you get the y interceptthen y=0+6solve for y, y=6
The x and y axis cross at (0,0) on the coordinate plane.
This is an equation of a straight line. There is no 'one solution' for x and y. The line will cross the y-axis at y = 6, and the slope is -3.