Eterna Forest
no
the old chateua inside the tv there is a rotom
To find rotom in Pokemon diamond you go 2 the old chateua in Eterna Forest and go 2 the middle room upstairs and then go to the room with the TV Rotom's in the TV. Hope I Helped.
u can't sorry :P u have to get it in Pokemon black or white then trade it to ur game in soul silver, if it lets u
You will find a Pokemon called "Rotom" in the Old Chateau near the exit of Eterna Forest. It is in one of the rooms upstairs, and you encounter it in battle by going up to a flashing television set and pressing the A button. It is only level 17 though, so be careful. It only appears at night, and I believe it is and Electric-Ghost type.
Gastly is in Old Chateau and Lost Tower. Drifloon is in Valley Windworks on Friday. Misdreavus is in Lost Tower. ( Pearl Only) Rotom is post ending Old Chateua. Banette is on Route 225 at night. Dusclops is on route 227. Giratina(!!!!) is in Turnback Cave. You can migrate Nincada and Snirnut to get Frosslass and Shedninja. Spiritomb is very hard to get. And, Sableye should be migrated. P.S: Why do you wanna no?
The girl in the old chateua is the 2nd badge gym leader... There's a legendary Pokemon name rotom in the TV in the old chateau.. To get rotom the DS clock should be set on night, in exception to Pokemon platinum you can catch rotom as soon as you defeated the 2nd badge gym leader... Rotom is at lvl 20, you must bring a Pokemon with sleep powder and few great balls...
OLD LADY, OLD HAGE, OLD BOY, OLD MAN,OLD KID,OLD DOG ,OLD GIRL, OLD CAT ,OLD WOLF,and thats all folks
old is 50+ and very old (old old) is 80+.
a old person is qualified to be old when there over the age of 60 years old.
old as your grandma, if shes dead then..i have no idea
The original question was too long to copy in. It was: "The sum of the ages of Old and Young is 48. Old is twice as old as young was when old was half as old as young will be when young is three times as old as old was when old was three times as old as young How old is old?" There is a rather strenuous algebraic solution.The answer is :Old is 30, Young is 18When Old was 18, Young was 6; when Old was 27 (1/2 of 54), Young was 15, and Old is twice that.If you change the sum to 32, then the ages become 20 and 12.When Old was 12, Young was 4; when Old was 18 (1/2 of 36), Young was 10.In each case, Old is always 5/3 as old as Young and 5/8 of the sum.