0
Weight
What else can I help you with?
A box is sitting on a table. The upward force exerted on the box that stops it from falling through the table is known as the force.?
A box is sitting on a table. The upward force exerted on the box that stops it from falling through the table is known as the force.
What force stops a box from falling through a table if it sits on top of it?
The force that stops a box from falling through a table is the normal force. This force is exerted by the table in the upward direction and counteracts the downward force (weight) of the box, preventing it from falling through the table.
What is the upward force that keeps a box on a table known as?
The upward force is the reaction force of gravity; it is weight, which is mass x acceleration of gravity
What types of force exists for every other force?
Reactive force. For every action there is an equal but opposite reaction. So if a box is sitting on the table, and the box weighs one kg, it exerts 9.81N of force on the table. Likewise, the table exerts 9.81N of force on the box in order to keep the box on the table. Otherwise, the box would smash through the table. THESE TWO FORCES ARE EQUAL BUT OPPOSITE, SO THE SUM OF THE TWO WILL ALWAYS BE EQUAL TO ZERO.
What forces are acting on a box resting a table?
The main forces acting on a box resting on a table are the gravitational force pulling it downwards and the normal force exerted by the table supporting the weight of the box. These forces are balanced when the box is at rest.
When will the frictional force be greater than the force of you pushing a box across a table?
The frictional force will be greater than your pushing force when the surfaces are rough, creating more resistance. This can happen if there are high levels of friction between the box and the table or if the weight of the box increases significantly.
Why a man lifting a box to be placed on a table is work?
In physics, work is performed when a force is applied to an object and causes it to move in the direction of the force. In this scenario, the man lifting the box is applying a force to move the box upwards against the force of gravity. The work done is equal to the force applied multiplied by the distance the box is lifted.
What is the force of gravity of a box that has a total mass of 20kg and is placed on a table with two people putting forces of 20N and 40N on the box in the same direction horizontal and to the right?
Assume we can ignore friction when answering this question.
Every force has what type of force?
Reactive force. For every action there is an equal but opposite reaction. So if a box is sitting on the table, and the box weighs one kg, it exerts 9.81N of force on the table. Likewise, the table exerts 9.81N of force on the box in order to keep the box on the table. Otherwise, the box would smash through the table. THESE TWO FORCES ARE EQUAL BUT OPPOSITE, SO THE SUM OF THE TWO WILL ALWAYS BE EQUAL TO ZERO.
Which describes how sliding friction affects pushing a cereal box across a table top?
Sliding friction opposes the motion of the cereal box as it is pushed across the tabletop. This frictional force arises from the interaction between the box's surface and the table, requiring you to exert additional force to keep it moving. The greater the weight of the box or the roughness of the table surface, the higher the sliding friction, making it more challenging to push the box. Ultimately, sliding friction acts as a resistance that must be overcome to maintain movement.
Is their a difference in the sound produced when the ruler is placed across the box?
Yes, when the ruler is placed across the box and the box is struck, the sound produced is clearer and louder compared to when the ruler is not there. This is because the ruler acts as a bridge, transmitting vibrations more effectively from the box to the surrounding air.
Does the box slide if the coefficient of friction of the box on the table is 0.4 with a horizontal force of100N acting on a 20kg box?
F=0.4(n) where f is force required to move box form resting (static) position and n is the normal force applied by the surface of the table. So F=.4x20kg=8kg. 8kg are required to overcome resisting force due to friction. 8kg=Appox. 78N. 78N of force is required to overcome resisting force due to friction.
