0
Nokia C3 is better then the 5322 nokia.
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What is puk code for nokia c3?
it also happen to my cell phone... they say that the problem is from your SIM not from your phone...
What are the release dates for The Bold and the Beautiful - 1987 1-5322?
The Bold and the Beautiful - 1987 1-5322 was released on: USA: 29 May 2008 Belgium: 18 February 2011
Can you download whatsapp a Nokia C2 03?
Method 1 :Download Whatsapp for S40 From through your Phone BrowserInstall it like any other Java Application.Method 2: Go to whatsapp downloadClick on the link Called "Download for Nokia S40 from our site".Download & Install it on your Nokia C2-02 / C2-03 / C2-05 phone.Source:idadtech.com
Factor c4 c3 - c2 - c?
If that's + c3, the answer is c(c - 1)(c + 1)(c + 1)
What is the price of Nokia X-1?
the pice of nokia x-1 is 2,199
Who do you call to report radio wave abuse?
The Federal Communications Commission can handle this problem. Phone: 1-888-225-5322
Top five Nokia phones?
NO.5 Nokia 5310 Xpressmusic NO.4 Nokia n97 20 GB NO.3 Nokia n95 NO.2 Nokia n95 8GB NO.1 Nokia n96 16GB!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Antivirus for 6500s-1 nokia mobile free download?
use this its the better than the rest yazing vipreantivirus/sheie
Does nokia have a flagship store in Shanghai?
Nokia has a flagship store in Shanghai that opened in 2007. On April 1, 2014, Nokia decided to close it.
How do you evaluate c to the negative 3?
C-3 = 1/(c3)
How do you reset nokia 5610d 1 security code?
I do not knowDo you know..??
Write a program to find sum of two complex numbers?
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
