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[Xe] 4f3 6s2
The electron configuration of americium is [Rn]5f7.7s2.
alkali metals need to loose one electron. alkali earth metals need to loose two
Neon
Potassium must lose one electron (to have the same configuration as the noble gas argon), and fluorine must gain one electron (to have the same configuration as neon)
No - but the potassium ion does
[Xe] 4f3 6s2
Cs does not have a nobel gas electron configuration, as it contains one valence electron in its outermost s orbital. Be3+ also does have a nobel gas electron configuration, as this occurs when Be has a 2+ charge (the typical Be ion is Be2+).
Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration. Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration.
The electron configuration of americium is [Rn]5f7.7s2.
I assume you mean the Nobel gas electron configuration abbreviation for barium.[Ne] 6s2=======
If you think to the electron configuration of promethium this begin with [Xe].
1
alkali metals need to loose one electron. alkali earth metals need to loose two
The Alkali Metals loose one electron in order to achieve a nobel gas configuration.
Helium IS a Nobel gas and heads that group. It may not have the full 8 electron octet, but it is just as naturally non-reactive as the other Nobel gases.
Gaining of 1 electron take Fluorine to nobel gas state