How do you write the standard form of the equation for the line that passes through the points -8 and-7 and -5 and -5?
(- 8, - 7) and (- 5, - 5)Need slope first. m = Y2 - Y1/X2 - X1m = - 5 - ( - 7)/- 5 - (- 8)m = 2/3========Now, I use point slope form to get us half way thereY - Y1 =m(X - X1) ( - 8, - 7) points usedY - (- 7) = 2/3[X - (- 8)Y + 7 = 2/3(X + 8)Y + 7 = (2/3)X + 16/37 = 21/3, soY + 21/3 = (2/3)X + 16/3Y = (2/3)X - 5/3===========================standard form