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Group 1- as the configuration is ns1. The Kr in the question indicates the Krypton core. The 5s1 is the clue - the period number is the same as the principal quantum number (in this case 5) so the element is in group 1 and period 5 - so it is rubidium.

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15y ago
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8y ago

Sr has the above electron configuration. Sr has 38 electrons.

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11y ago

Yes, it is true.

See also the link below.

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14y ago

Period 5, Group 1

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11y ago

This would be Technetium.

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8y ago

This element is strontium (Sr).

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11y ago

silver

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11y ago

Xenon.

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Q: What element has the electron configuration of Kr 5s2 4d10 5p3?
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Related questions

What is the electron configuration of stibium?

The electronic configuration of stibium (antimony) is: [Kr]4d10 5s2 5p3.


What is the noble gas configuration for antimony?

[Kr]4d105s25p3


What is the noble gas configuration of antimony?

[Kr]4d105s25p3


What has this noble gas notation of Kr 5s2 4d10 5p3?

there are 51 electrons in all. So the atomic number of the element is 51 and the element is antimony.


What is the noble gas shorthand of antimony?

[Kr] 4d10 5s2 5p3


What is the noble gas notation of antimony?

[Kr] 4d10 5s2 5p3


What is the noble gas for Sb?

Sb (antimony) has 51 electrons. Its noble gas notation is [Kr] 4d10 5s2 5p3


What is the orbital diagram of antimonium?

Antimony Sb atom number 51, electronconfiguration:per shell: (K,L,M,N,O) = 2, 8, 18, 8+10, 5per orbital: [1s2, 2s2 2p6, 3s2 3p6 3d10, 4s2 4p6]4d10, 5s2 5p3short writing: [Kr] 4d10 5s2 5p3


What is the noble gas notation for Sb?

Sb (antimony) has 51 electrons. Its noble gas notation is [Kr] 4d10 5s2 5p3


How many electrons are in the lowest occupied energy level in a Group 4A element?

It would be 3 electrons!Why?Antimony: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p3 Nitrogen: 1s2,,2s2,2p3Phosphorus: 1s2 2s2 2p6 3s2 3p3Arsenic: 3d10 4s2 4p3Bismuth: 4f14 5d10 6s2 6p3so on..


How many permutations are there in any 3 from 5?

There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.


How may combinations of three can you get from five?

60 if you allow permutations, 20 if not. 60 is found by suing the permutation function 5P3, and we get 20 simply by dividing by 3 as there will be 3 permutations from a group of 3 numbers while keeping the order the same e.g. (1,2,3) , (2,3,1) and (3,1,2).