Bullseye: *Whistles* Ha ha ha!
Daredevil: That's him... That's your father's... Don't...
Elektra: He has to pay for what he's done.
Daredevil: I don't want to lose you again.
Bullseye: Ha ha ha! Come on, girl!
Elektra: I'll find you.
Bullseye: *Whistles at Elektra* Ha Ha Ha! Hey orphan, let's play!
No probability. Neither parent has an "A" for the child to inherit to make an "AB".
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
A genotype is decided from two alleles. One of these alleles comes from the father, and one comes from the mother. Thus it should be clear that the genotype can be different from both parents. For instance, suppose the father has genotype AA, and the mother has genotype aa. In this case, the child will have genotype Aa, which neither parent has.
No because AA and SS create the genotype AS :)
The parents pass along genes to the child
ff (apex)
ff (apex)
PHENOTYPE: 75% with freckles 25% without freckles GENOTYPE: 1FF:2Ff:1ff
BIBOB
An individual with the genotype Ff is heterozygous for a trait, meaning they have one dominant allele (F) and one recessive allele (f). If the trait in question is freckles, the dominant allele (F) would typically result in the presence of freckles, while the recessive allele (f) would lead to no freckles. Therefore, a person with the Ff genotype is likely to have freckles. If they were homozygous recessive (ff), they would not have freckles.
No probability. Neither parent has an "A" for the child to inherit to make an "AB".
The man's genotype is CcFf. The woman's genotype is CcFf. These genotypes only apply if curly hair is dominant to straight hair. Freckles is dominant to no freckles. Also if a man who is heterozygous for both curly hair and freckles who then marries a woman with the same genotype.
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
Yes, if they both carry a recessive (hidden gene) for freckles, then yes their child would have a 25% chance of having freckles.
Yes it depends on their genes
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
The sun will make freckles more prominent/noticeable.