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A man and a woman are both heterozygous Freckles are dominant over no freckles What are the chances their children will have freckles?
There is a 75% chance that their children will have freckles and a 25% chance that their children will not have freckles. This is because both parents are carriers of the freckles allele and can pass it on to their offspring.
A man with freckles and a women without freckles with 3 kids with freckles and 1 without what is the genotypes of the parents and children?
The man must have a dominant gene for freckling and a recessive gene for no freckling. The woman has both recessive genes for no freckling. Therefore, there should be a 50% chance of getting the freckling gene and freckle in this family. If they had more children, chances are 50/50 that the baby will freckle.
What are the chances that two parents who are heterozygous dominant for two?
If both parents are heterozygous dominant for two traits (e.g., AaBb), the chances of their offspring exhibiting different combinations of these traits can be analyzed using a Punnett square. Each parent can produce four types of gametes (AB, Ab, aB, ab), leading to a 16-cell Punnett square. The probability of specific trait combinations can be calculated from this square, revealing that the expected phenotypic ratio for two independently assorting traits is typically 9:3:3:1 for the dominant and recessive traits. Thus, the specific chances depend on the traits in question.
If flower color is determined using incomplete dominance where red is dominant white is recessive and pink is heterozygous. What are the chances that a red flower and a pink flower will reproduce to m?
In a cross between a red flower (homozygous dominant, RR) and a pink flower (heterozygous, RW), the possible offspring genotypes would be 50% red (RR) and 50% pink (RW). Therefore, the chances of producing a red flower are 50%, while the chances of producing a pink flower are also 50%. There would be no chance of producing a white flower in this scenario.
Which is the dominant gene father has dark brown eyes mother has blue eyes?
Sure you don't mean heterozygous dominant? If you don't there would be no blue eyed offspring. Let's assume you meant heterozygous dominant.B = brownbl = blueBbl X Bbl1/4 of the offspring would have blue eyes, 25%.
What are the chances of getting Huntington's if one of your parents are heterozygous?
If one of your parents is heterozygous for Huntington's disease, you have a 50% chance of inheriting the mutated gene responsible for the condition. This is because Huntington's is an autosomal dominant disorder, meaning that only one copy of the mutated gene is needed to develop the disease. If you inherit the normal allele from the heterozygous parent, you won't develop the disease.
What are the chances for each genotype in a heterozygous cross using Mendelian Genetics?
In a heterozygous cross (e.g., Aa x Aa), the chances for each genotype can be determined using a Punnett square. The possible genotypes are AA, Aa, and aa. The probabilities are 25% for AA, 50% for Aa, and 25% for aa. Thus, the phenotypic ratio would typically be 3:1 if A is dominant over a.
How do you prove gene dominance?
When two heterozygous organisms are mated, approximately 75% of these organisms should display the trait if it is dominant. 25% would display the recessive gene. If these numbers are very far off, chances are the gene you were testing was not a dominant trait.
Black hair is dominant over blond hair A blackhaired woman and a blondhaired man reproduces What are the chances of this couple having a blond -haired child?
The chance of this couple having a blond-haired child is 0%. Since black hair is dominant, both the parents must be heterozygous for hair color (Bb for black hair and bb for blond hair) for the man to be blond. If both parents are heterozygous, they would have a 25% chance of having a blond-haired child. However, if the woman has black hair, she must be homozygous dominant (BB) and the child would inherit at least one dominant allele for black hair.
Why do children have characteristics of both their mother and father?
Children have similar characteristic's to their parents because when they are conceived, both of the parents genes unify to create a new set of characteristic'd depending on dominant and recessive traits. For example, Jane and Henry find out they are having a baby. Jane has homozygous blue eyes whilst Henry has heterozygous brown eyes. The chances are that their baby will either have 50% homozygous blue eyes or 50% heterozygous brown eyes.
What are the chances of inheriting two p alleles?
The chances of inheriting two p alleles depend on the genetic makeup of the parents. If both parents are heterozygous for the p allele (Pp), there is a 25% chance their offspring will inherit two p alleles (pp). If one parent is homozygous dominant (PP) and the other is homozygous recessive (pp), the offspring will not inherit two p alleles. Thus, the inheritance pattern is influenced by the genotypes of the parents.
What are the chances of having kids that can roll their tongue if a heterozygous tongue roller has kids with someone who cannot roll?
If one parent is heterozygous for the tongue rolling gene (Tt) and the other parent cannot roll their tongue (tt), the chances of their children being tongue rollers (Tt) is 50%. The other 50% chance is that the children will not be able to roll their tongue (tt).
