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Which genotypes are possible for offspring of a carrier (Ss) and a person who lacks the sickle-cell allele (SS)?
SS,Ss
What else can I help you with?
For sickle-cell disease assume S is the dominant allele and s the recessive allele Which genotypes are possible for offspring of a carrier (Ss) and a person who lacks the sickle-cell allele (SS)?
SS,Ss
How many genotypes are possible in a pedigree of sex linked traits?
In a pedigree of sex-linked traits, there are three possible genotypes for males: XY (unaffected), XeY (affected), and XeX (carrier). For females, there are two possible genotypes: XX (unaffected) and XeX (carrier). This makes a total of 5 possible genotypes in a sex-linked trait pedigree.
A girl is a hemophiliac whose mother is normal what are the genotypes of her parents?
The girl must have inherited an X chromosome with the hemophilia gene from her mother, who is a carrier (heterozygous X^HX^h). The father must have contributed a Y chromosome, as males determine the offspring's sex. The father's genotype is not directly related to the daughter's hemophilia status.
What does the punnett square show of a carrier girl and a colorblind boy?
you have to determine what traits are used before you can do it and look at punnett square
Can you correctly label the phenotypes in this Punnett square of a sex-linked cross?
To label the phenotypes in a Punnett square of a sex-linked cross, first identify the alleles involved, typically denoted as X^A (dominant) and X^a (recessive) for a trait linked to the X chromosome. The genotypes of the parents will determine the potential offspring combinations. For example, if a female is X^A X^a and the male is X^A Y, the Punnett square will show the possible offspring: X^A X^A (normal female), X^A X^a (carrier female), X^A Y (normal male), and X^a Y (affected male). Label each box according to these genotypes to visualize the associated phenotypes.
An individual with a recessive allele for an undesirable trait is called?
A carrier. This individual may not show the undesirable trait, but can pass on the recessive allele to their offspring.
What are the possible genotypes of the parents with albinism?
Individuals with albinism typically have a recessive genetic trait, meaning they must inherit two copies of the albinism gene (aa) to express the condition. Therefore, the possible genotypes of the parents could be either both carriers (Aa), one carrier and one affected (Aa and aa), or both affected (aa). If both parents are carriers, there is a 25% chance for each child to be affected by albinism.
What are the genotypes of Alice of Hesse and Leopold Duke of Albany?
The genotype of Alice of Hesse is Tt and Leopold is tt.
Why is a son who receives the allele for combinations from his mother always colorblind?
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
A carrier of a genetic disorder who does not show symptoms is most likely to be to transmit it to offspring?
A carrier of a genetic disorder who does not show symptoms is most likely to be heterozygous for the trait and able to transmit it to his offspring. The term heterozygous refers to a pair of gene with one dominant trait and one recessive trait.
Is a person who is homozygous recessive for a recessive genetic disese a carrier?
As long as a persons genotype consists of at least one recessive gene, they can pass it on to offspring to give them the disease, which makes them a carrier. Since this persons genes are both recessive, it is definite that they will pass on the recessive gene.
If a dominant homozygous reproduced with a heterozygous could their offspring be recessive?
Let's see what combinations can be formed.HH, HH, Hh, Hh.So, yes their offspring can contain the recessive allele.(THe offspring can be a carrier of the recessive allele.)However, since it is impossible for the offspring to be homozygous recessive,the recessive trait/gene will not show in the offspring's phenotype.Hope that helps!
