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Answered 2010-07-24 21:47:22

CH3Br has a higher boiling point.

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CH3OH has the highest boiling point of the three.

This is carbon tetrachloride with the boiling point +76,72 oC.

NH3 is heavier then CH4, and NH3 has hydrogen bonding.

Metahne does not have a higher boiling point than methane. Fluoromethane, CH3F, has a boiling point of 195K, -78.2C, methane, CH4, has a boiling point of 109K approx -164 C. I make that fluoromethane has a higher temeprature boiling point than methane. This is what you would expect, London dispersion forces will be greater in CH3F as it has more electrons than CH4. CH3F is polar and there will be dipole dipole interactions which will not be present in CH4.

CH3Br is a polar molecules, meaning that one end of the molecule has a partial positive charge wile the other has a partial negative charge. This causes the molecules to be attracted to each other in much the same manner as magnets., making it harder to turn the substance into gas. Methane, by contrast, is nonpolar and so this effect does not apply to it. CH3Br also has greater molar mass , which gives it stronger "Dispersion" London Forces (inter molecular forces) increasing its boiling point more than the CH4 But this is a relatively minor factor compared with polarity

CBr4 is larger than CH4, so it has a higher London dispersion, a type of Intermolecular force. Higher force means longer time to bring the substance to boil, thus a higher boiling point.

SiH4. since it's mass is larger then CH4, London constraints are stronger.

Yes, Boiling point of ammonia, NH3: - 33,34 0C Boiling poit of methane, CH4: - 161,6 0C

ch3nh2, because it has hydrogen bonding going on.

Due to H bonds NH3 has high boiling point.CH4 has weak London forces

No. CH4 has a very low boiling point of about -162 degrees C.

Methane (CH4) is a gas; the boiling point is at -164 0C.

NH3 is a polar molecule, so the molecules attract each other like magnets.CH4 is completely symmetrical, so it is non polar.Therefore, NH3 has a higher boiling point because it takes more energy to knock its molecules away.

The bonds between H and O are stronger than the bonds between C and H.

Both NH3 and HCl exhibit hydrogen bonding as intermolecular forces, whereas CH4 does not. This makes CH4 have a lower boiling point. Since there are 3 hydrogen atoms in NH3 and only 1 in HCl(g), the intermolecular forces would be expected to be greater in NH3 than in HCl.

Because octane has more carbons, and the more carbons you have the higher the melting point. also octane is a gas that is very close to nonane (which is the first liquid) and that would mean it has a larger boiling point that methane (which is a gas that is the first one CH4). that is why octane has a larger boiling point that methane. Also, you can also figure it out the boiling points of each and look at the differences.

Chloromethane, or CH4, is a haloalkane, and the most abundant organohalogen in the atmosphere. It has a boiling point of -23.8 degrees Celsius.

It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr

Methane + Bromine --> Bromomethane + Hydrogen bromide

CH4(g) + Br2(g) -----------------> CH3Br(g) + HBr(g) (sunlight/UV Light)

CH4, due to the least number of carbon atoms.

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