Want this question answered?
1 mole of helium has 6.023 x 1023 atoms. So, 1.5 mole of helium will have 9.035 x 1023 atoms.
1 mole has 6.023 x 1023 atoms So, in 3.05 moles there are 18.37 x 1023 atoms
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
1 mole atoms of all atoms of any element will always have the same number of atoms and will be equal to 6.023 x 1023 atoms. However the weight will vary. 1 mole = 4 g of Helium or 197 g of gold or 207 g of lead
1 mole of helium has 6.023 x 1023 atoms. So, 1.5 mole of helium will have 9.035 x 1023 atoms.
1 mole = 6.0 x 1023 atomsSo, 4 mole = 24 x 1023 atoms or 2.4 x 1024 atoms
1 mole has 6.023 x 1023 atoms So, in 3.05 moles there are 18.37 x 1023 atoms
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
Using avagadro's number of 6.022 x 10 to the 23rd atoms/mole. The answer is 1.99 moles of gold
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
1 mole atoms of all atoms of any element will always have the same number of atoms and will be equal to 6.023 x 1023 atoms. However the weight will vary. 1 mole = 4 g of Helium or 197 g of gold or 207 g of lead
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2
using the formula: n=m/gfm no. of moles=mass/gfm you take the gram formula mass (gfm) as 4. and given the mass is 16g, both numbers can be substituted into the formula... n=16/4 = 4 the number of moles present in 16g of helium is 4 moles.
2.61 X 10^24 atoms of gold (1 mole Au/6.022 X 10^23) = 4.33 moles of gold
5 moles of helium He atoms is equivalent to 20,013 g.