Just multiply the width and the length for a rectangle or a square. The answer is 884cm squared.
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
Largest = 86, Smallest 26
Let the width be x, so the length is 2x - 4. Since one half of the perimeter is 26 feet ( 52/2), then we have:x + (2x - 4) = 263x - 4 = 263x - 4 + 4 = 26 + 43x = 303x/3 = 30/3x = 102x - 4 = 2(10) - 4 = 20 - 4 = 16Thus the width of the rectangular garden is 10 feet, and the length is 16 feet.
Let the length be 2x-3 and the width be x:- So: 2*(2x-3+x) = 82 feet => 6x-6 = 82 => x = 14 and 2/3 Therefore the dimensions are: length = 26 ft 4 ins and width = 14 ft 8 ins
If it's a rectangle then:- Area = 9*4 = 36 square meters Perimeter = 9+4+9+4 = 26 meters
884 cm squared Area of a rectangle is length times width, so it is simply 26 cm x 34 cm.
it is 884
The area of the rectangle is: 5 times 8 = 40 square inches
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
24 feet square feet
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
The Area of a rectangle is calculated by multiplying the length by the width. For a pool with a length of 26m and a width of 11m, you can then calculate the area simply by multiplying these two values together:Area = 26 x 11 = 271m^2
Its impossible to isolate both the length and width, but you can figure out the sum of one pair of length and width, which is 13.
Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm
4 feet
4 feet
Draw the table and calculate the area of the triangle the area of a square is 36